Complete question :
Two researchers, Jaime and Mariya, are each constructing confidence intervals for the proportion of a population who is left-handed. They find the point estimate is 0.13. Each independently constructed a confidence interval based on the point estimate, but Jaime’s interval has a lower bound of 0.097 and an upper bound of 0.163, while Mariya’s interval has a lower bound of 0.117 and an upper bound of 0.173. Which interval is wrong? Why?
Answer:
Mariya's interval
Step-by-step explanation:
Point estimate = 0.13
Mariya's confidence interval :
Lower boundary = 0.117
Upper boundary = 0.173
Jamie's confidence interval :
Lower boundary = 0.097
Upper boundary = 0.163
The correct confidence interval should have an average value equal to the value of the point estimate ;
Jamie's confidence interval average :
(0.097 + 0.163) / 2 = 0.26 / 2 = 0.13
Mariya's confidence interval average :
(0.117 + 0.173) / 2 = 0.29 / 2 = 0.145
Based on the confidence interval average obtained we can conclude that Mariya's interval is wrong as it the average obtained is greater than the point estimate.
0.145 > 0.13
Answer:
1.7
Step-by-step explanation:
Adding together all the points, you get 10. 10 divided by 7 is 1.666666667, which rounds to 1.7
Yes because of the positive association it holds. I’m not sure if this is actually true or not but if there’s a correlation between them then yes
Part A
<h3>Answers:</h3>
To find the area of the unshaded region, subtract the area of the <u> shaded region </u> from the sum of the areas of the <u> rectangle </u> and <u> semicircle </u>
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Explanation:
When it comes to area problems, think of a grid of squares. Let's say we had a 10 by 10 grid of tiny squares (10*10 = 100 total). Now let's say 8 of them are shaded in. There are 100 - 8 = 92 unshaded squares to represent the total area of the unshaded region.
That's effectively what's going on with this problem as well. Sure things get a bit tricky with that curved portion on top, but we can still get an approximation if we use smaller and smaller grid sizes. I recommend using graph paper or graphing software that provides a grid.
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Part B
<h3>Answer: 811</h3>
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Explanation:
For now, I'm going to ignore the shaded region. I'll come back to it later.
The rectangle is 15 ft by 50 ft. It has an area of length*width = 15*50 = 750 sq ft.
The semicircle up top has an area of
sq ft approximately. The 7.5 is from dividing the diameter in half to get the radius. As the instructions stated, I used the calculator's version of pi.
The rectangle and semicircle have their areas add to
750+88.3573 = 838.3573
Now we can finally address the shaded region. It is a 3 ft by 9 ft rectangle because "the length is 3 times the width" and the width is 3 ft. This shaded rectangle has area 3*9 = 27 sq ft.
The unshaded region is:
unshaded = total - shaded = 838.3573 - 27 = 811.3573
This rounds to the final answer of 811