Someone please help me with this

Kyra has a rock collection.When she puts her rocks into 2 equal piles,there are no rocks left over.When she puts her rocks into

liubo4ka [24]

any multiple of 12

Since 2, 3 and 4 divide exactly into the number of rocks

We are looking for the common multiples of 2, 3 and 4

2 × 3 × 4 = 24 is possible but dividing by 2 gives 12 the lowest common multiple

Any multiple of 12 gives a possible number of rocks.

8 0

3 years ago

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

3 years ago

A supervisor records the repair cost for 17 randomly selected VCRs. A sample mean of $68.83 and standard deviation of $12.17 are

amid [387]

Answer:

27

Step-by-step explanation:

im smart

5 0

3 years ago

Juan put three square tiles with sides 8 centimeters, 10 centimeters, and x centimeters together so that they form a right trian

Elan Coil [88]

Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to $x^{2}$ .
$A = x^{2}$ ---> equation (1)
By using pythagoras rule which states that the $x^{2} = hyp^2 - opposite^2$ ---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
$x^{2} = 10^{2} - 8^{2}$ substitute this value in equation (1) then
$A = x^{2} = 10^{2} -8^{2}$
where A is the area of the square whose side is x

6 0

2 years ago

Read 2 more answers

I need help I'm stuck

ankoles [38]

Then put in some butter that will get you out

8 0

3 years ago