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Illusion [34]
3 years ago
7

Scientists predict that there is a 0.8 chance that there will be an earthquake in San Francisco this year. How likely is that th

ere will be an Earthquake?
Mathematics
1 answer:
Firlakuza [10]3 years ago
8 0

Answer:

80%

Step-by-step explanation:

You might be interested in
Omari and his two cousins received the same amount of money to go to the movies. Each boy spent $15. Afterward, the boys had $30
Jlenok [28]

Answer:

Each boy recieved $25.25 each

Step-by-step explanation:

First, you add up all the money the 3 boys spent.

15+15+15=45

Then you add the sum of the equation to the amount all the boys had afterward.

45+30.75=75.75

Finally, you divide that product to 3 boys.

75.75/3=25.25

Therfore the answer is $25.25 each.      

6 0
3 years ago
A farm packages eggs into cartons that hold two dozen eggs each. Last week, 5,398 eggs were collected. How many cartons will the
Sonbull [250]

Answer:

225

Step-by-step explanation:

We're told that each carton holds two dozen eggs, or 24 eggs. To find out how many cartons the farm will need, we divide the total amount of eggs by the amount of eggs that fit in each carton. So:

\frac{5398}{24} = 224.916667

Since the number is a decimal, you need to round up to make sure every egg is in a carton. So, your answer is 225.

4 0
2 years ago
What is the solution to the equation 9(w – 4) – 7w = 5(3w – 2)?
cluponka [151]

Answer:

-2

Step-by-step explanation:

9w-36-7w=15w-10

2w-36=15w-10

-13w=26

w=26/(-13)

w=-2

3 0
3 years ago
This math my graduation depends on it
In-s [12.5K]

In an arithmetic sequence, consecutive terms have a fixed distance d between them. If a₁ is the first term, then

2nd term = a₂ = a₁ + d

3rd term = a₃ = a₂ + d = a₁ + 2d

4th term = a₄ = a₃ + d = a₁ + 3d

and so on, up to

nth term = a_n = a_{n-1} + d = a_{n-2} + 2d = a_{n-3} + 3d = \cdots = a_1 + (n-1)d

so that every term in the sequence can be expressed in terms of a₁ and d.

6. It's kind of hard to tell, but it looks like you're given a₁₃ = -53 and a₃₅ = -163.

We have

a₁₃ = a₁ + 12d = -53

a₃₅ = a₁ + 34d = -163

Solve for a₁ and d. Eliminating a₁ and solving for d gives

(a₁ + 12d) - (a₁ + 34d) = -53 - (-163)

-22d = 110

d = -5

and solving for a₁, we get

a₁ + 12•(-5) = -53

a₁ - 60 = -53

a₁ = 7

Then the nth term is recursively given by

a_n = a_{n-1}-5

and explicitly by

a_n = 7 + (n-1)(-5) = 12 - 5n

7. We do the same thing here. Use the known terms to find a₁ and d :

a₁₉ = a₁ + 18d = 15

a₃₈ = a₁ + 37d = 72

⇒   (a₁ + 18d) - (a₁ + 37d) = 15 - 72

⇒   -19d = -57

⇒   d = 3

⇒   a₁ + 18•3 = 15

⇒   a₁ = -39

Then the nth term is recursively obtained by

a_n = a_{n-1}+3

and explicitly by

a_n = -39 + (n-1)\cdot3 = 3n-42

8. I won't both reproducing the info I included in my answer to your other question about geometric sequences.

We're given that the 1st term is 3 and the 2nd term is 12, so the ratio is r = 12/3 = 4.

Then the next three terms in the sequence are

192 • 4 = 768

768 • 4 = 3072

3072 • 4 = 12,288

The recursive rule with a₁ = 3 and r = 4 is

a_n = 4a_{n-1}

and the explicit rule would be

a_n = 3\cdot4^{n-1}

7 0
2 years ago
Find the sum of 1 1/2 + 2/3
creativ13 [48]
Well first you would find a common denominator which is 6 the add your numerators to equal 1 7/6 then you would simplify it to equal 2 1/6.
8 0
3 years ago
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