Ask question

Ask question

All categories

3 years ago

9

What are the equivalent ratios shown in the table? Complete the statement.

2 answers:

Radda [10]3 years ago

6 0

I will !

This is five-fold proportion
The first ratio gives solution namely
We will write general proportion
a:b= c:d= e:f = g:h= i:j = k
According to this the first ratio gives coefficient k
When we divide 24/2 =12 our coefficient k=12

In the second ratio we will multiply 3 with 12 and get 36.
In the third ratio we will multiplu 5.5 with 12 and get 66.
In the fourth we will divide 108 with 12 and get 9.
In the fifth we will multiply 15 with 12 and get 180.

Finally the ratio is 24:2=36:3=66:5.5=108:9=180:15

Good luck!!!!

Troyanec [42]3 years ago

5 0

Answer:21

Step-by-step explanation: memes

You might be interested in

5) |-16 |- |-2|<br> Evaluate

larisa86 [58]

Answer:

16 - 2 = 14

Step-by-step explanation:

The lines mean absolute value and the absolute value of -16 is and of -2 is 2

8 0

3 years ago

Read 2 more answers

Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store so

Artemon [7]

Answer is b 150p(250-p)150p(250-p

5 0

3 years ago

Does anyone know??????

masha68 [24]

Answer:

y=23x+4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

7 0

4 years ago

Read 2 more answers

Write the number equal to 7 tens and 3 ones

Sergeu [11.5K]

7tens= 70 3ones= 3
So 70+3=73

4 0

3 years ago

Read 2 more answers