The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
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To solve this problem, we have to manually
solve for the value of x for each choices or equations. The correct equation
will give a value of -1 since the linear equations intersects at point (-1,
-4).
<span>1st: 7x + 3 = x + 3</span>
7x – x = 3 – 3
6x = 0
<span>x = 0 (FALSE)</span>
<span>2nd: 7x − 3 = x – 3</span>
7x – x = 3 – 3
6x = 0
<span>x = 0 (FALSE)</span>
<span>3rd: 7x + 3 = x − 3</span>
7x – x = - 3 – 3
6x = -6
<span>x = -1 (TRUE)</span>
<span>4th: 7x − 3 = x + 3</span>
7x – x = 3 + 3
6x = 6
<span>x = 1 (FALSE)</span>
Therefore the answer is:
<span>7x + 3 = x − 3</span>
Answer:
x=7
Step-by-step explanation:
9x+20x+16+12x+10+7x-2=360
48x+24=360
48x=360-24
48 x=336
x=336/48=7
If you are given with all the tree sides of the triangle, you may solve for all the angles through the Law of Cosines,
c² = a² + b² - 2ab(cos C)
where angle C is the angle opposite the side c. You may use the same equation to get the values of the remaining angle. Additionally, if you already have one known angle, you can solve for the rest of the angles by Law of Sines,
a / sin A = b / sin B = c / sin C
3+1=h i beev this because you are adding the amount of adults to children then that would get you to h
