I need help with these two questions please!!!please HeLp mE

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).

zalisa [80]

Answer: 272

Step-by-step explanation:

Let a1=11

a2=20

a3=29

Formula for sequence=

an=a1+(n-1)d

an = nth term

a1= first term

n= nth position

d= common difference

We are looking for the 30th term,so our n=30

d= a2-a1

d= 20-11

d= 9

Using the formula

an= a1+(n-1)d

a30= 11+(30-1)9

a30= 11+(29)9

a30= 11+(29×9)

a30= 11+261

a30= 272

Therefore, the 30th term is 272

8 0

2 years ago

What is 73×28 in multiply with regrouping

klio [65]

First, u multiply 8x3. Only the 4 can go in the ones place so put the four beneath the line and put the 2 over the 7.
Multiply 8x7 and add 2.
Move to the tens place, do 2x3 then 2x7.
Add the products and put the comma. Then ur done

4 0

2 years ago

Convert the mixed number to an improper fraction. <br><br><br><br><br> 6 7/8

zepelin [54]

6 * 8 + 7 = 48 + 7 = 55

55/8

4 0

2 years ago

Read 2 more answers

I need help with this so could you give me the answers with an explanation if you can.

Katarina [22]

Answer:

$2.44745763 \times {10}^{6}$

Step-by-step explanation:

$R = \frac{ {x}^{2} }{y} \\ \\ = \frac{ {(3.8 \times {10}^{5}) }^{2} }{5.9 \times {10}^{4} } \\ \\ = \frac{14.44 \times {10}^{10} }{5.9 \times {10}^{4} } \\ \\ = 2.44745763 \times {10}^{10 - 4} \\ = 2.44745763 \times {10}^{6}$

4 0

3 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

4 0

2 years ago