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3 years ago

15

When is the median the most useful measure of central tendency?

2 answers:

Katarina [22]3 years ago

7 0

The median is the most useful when you want to find the average of something and you don't want the outlier to interfere.
Hope this helps! :D

vivado [14]3 years ago

4 0

If you want to find out the average of something.

You might be interested in

Is the pythagorean theorem true for all similar triangle

mojhsa [17]

False because you can only use the Pyth. Theorem on right triangles which may not necessarily be ALL similar triangles.

6 0

2 years ago

What’s the distance between (5,1)and(3,6)

laiz [17]

<u>How to Find the Distance Between Two Points</u>

Distance formula: d(P, Q) =√(x2 − x1)^2+(y2 − y1)^2

If you use this equation the answer will be 5.

4 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Find the slope of the line that passes through (4,2) and (9,1)?

pshichka [43]

Answer:

The slope of the line is $\displaystyle -\frac{1}{5}$ .

Step-by-step explanation:

We are given two coordinate points:

$(4, 2)$
$(9, 1)$

We are asked to find the slope of the line.

We can use the rise-over-run formula to solve for the slope of the line.

$\displaystyle \text{slope} = \frac{\text{rise}}{\text{run}}\\\\\text{slope} = \frac{y_2-y_1}{x_2-x_1}$

However, we firstly need to name our coordinate points.

In math, we can label our coordinates using the following label system:

$(x_1, y_1), (x_2, y_2)$

Therefore, we can also label our coordinates as such:

$x_1 = 4$
$y_1 = 2$
$x_2 = 9$
$y_2 = 1$

Now, we can supply these values into the formula and solve for our slope, or a better known variable, <em>m</em>.

$\displaystyle m = \frac{1 - 2}{9 - 4}\\\\m = \frac{-1}{5}\\\\m = -\frac{1}{5}$

Therefore, our slope is $\displaystyle -\frac{1}{5}$ .

8 0

3 years ago

Read 2 more answers

Which solid, no matter at which angle you cut it, will always have a circle for a cross section?

BARSIC [14]

Sphere is ur answer to ur question

4 0

3 years ago