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krek1111 [17]
3 years ago
10

Please help this is urgent I will be giving brainlyest to the first and correct answer!!!!! This question will be worth a lot of

points too. Please do it right and fast this is really urgent! Tysm!

Mathematics
1 answer:
Kamila [148]3 years ago
8 0

Answer:

Step-by-step explanation:

Hope this helped (:

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Multiply:4x^3sqrt4x^2(2^3sqrt32x^2-x^3sqrt2x)
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8x^5\left(32\sqrt{2}x^2-\sqrt{2}x^4\right)

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3 years ago
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Avery has 125 animal stickers. She gave 5 animal stickers to each of her 10 friends. HoW many animal stickers she have left? Wha
Angelina_Jolie [31]

Answer:

75

Step-by-step explanation:

125-(5*10)        

125-(50)

75

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3 years ago
A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
netineya [11]

Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

4 0
3 years ago
Devin has started a lawn care service. He will charge a mowing fee of $7 plus $2 per square yard of lawn. He also offers trimmin
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Answer:7+2xy

Step-by-step explanation:apex

4 0
3 years ago
Read 2 more answers
Please help me with this
alexandr1967 [171]
Photo has the answer

8 0
3 years ago
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