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3 years ago

What is the value of the expression 10 + (fraction 1 over 2)4 ⋅ 48?

Mathematics

2 answers:

Lilit [14]3 years ago

8 0

10+ 1/2*4*48 so take 10 plus 4 then multiply 48 then divide by 2... 336

djverab [1.8K]3 years ago

3 0

10 + 1/2*4*48 => 10 + 2*48 => 10 + 96 = 106.

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work out the equation of the line which passes through the point(-1,2)and is parallel to the line y=x+4

erma4kov [3.2K]

If you have graph paper (or regular paper, graph is easier) you can plot it out. The equation would be y=x-1
just graph the point and then go up one over one until you get cross the y-axis

3 0

3 years ago

2+0.4+0.06+0.002 whats tHe nUMBER iN sTAnDARD fORM

sveticcg [70]

Answer:

2.462

Step-by-step explanation:

I added up the decimals.

2+0.4=2.4

2.4+0.06=2.46

2.46+0.002=2.462

And I got 2.462 as my final sum.

6 0

2 years ago

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

2 years ago

ollegr [7]

Answer:

x = 2

y = -3

z = 4

( 2 , -3, 4 )

Step-by-step explanation:

x + y + z = 3 ---- i

x – y =5 ---- ii

y - z = -7 ---- iii

ii + iii

x - z = -2 ---- iv

i + ii

2x + z = 8 --- v

iv + v

3x = 6

x = 2

x=2 substitute for v

z = 4

x =2 substitute for ii

y = -3

5 0

3 years ago

Anyone know how to answer this question

mart [117]

9514 1404 393

Answer:

(x +6)^2 +(y -10)^2 = 225

Step-by-step explanation:

The standard form equation for a circle is ...

(x -h)^2 + (y -k)^2 = r^2

where the center is (h, k) and the radius is r.

The center of a circle is the midpoint of any diameter. The midpoint between two points is the average of their coordinates.

((-15, -2) +(3, 22))/2 = (-15+3, -2+22)/2 = (-6, 10)

The radius can be found using the distance formula, or by simply putting one of the given points in the equation for the circle to see what the constant (r^2) needs to be.

(x -(-6))^2 +(y -10)^2 = (-15-(-6))^2 +(-2-10)^2

(x +6)^2 +(y -10)^2 = 81 +144 = 225

The equation of the circle is ...

(x +6)^2 +(y -10)^2 = 225

5 0

2 years ago