-55 is an integer.
It is not a whole number because it is negative.
It is not a natural number because it is not a whole number.
It is not irrational because it can be written as a fraction $-\frac{55}{1}$ .

7 0

4 years ago

What is the slope of the line through the points (6,-8)And (3,- 4)

Nina [5.8K]

Answer:

y=(-4/3)x

Step-by-step explanation:

you put the points into this equation to find the slope

(y2-y1)/(x2-x1)

now lets label the points

(6,-8)

x1=6 and y1=-8

(3,-4)

x2=3 and y2=-4

Input into equation

(-4-(-8))/(3-6)=

(-4+8)/(3-6)

4/-3

7 0

3 years ago

What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

7 0

4 years ago