Answer:
d = 12
c = 4
so I think d > c
Step-by-step explanation:
1 x 12 = 12
0.75 x 4 = 3
12 + 3 = 15
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...
<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>
<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>
<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
12 action films are shown.
This is because if the ratio is 1:2, that means that exactly half of the total amount of movies are action. Thus, to evaluate this problem, you would find half of 24.
Answer:
irrational number, non-repeating decimal
Step-by-step explanation:
√18 = √9·√2 = 3·√2.
√2 is an irrational, non-repeating decimal (my calculator shows it to be approx. 1.414213562..... )
and so √18 is the same.
Answer:
1. The minus before the |x| reflects the function in the x-axis. So it will still be V-shaped but instead but refected in the x-axis.
2. The +4 moves the function vertically 4 units upwards.
Step-by-step explanation:
We are given the function f(x) = - |x| +4. We know that the function f(x) = |x| only has positive values, so when x>0 the function is a straight line as in the function f(x) = x. When x<0 the function is also positive, as in the function f(x) = -x. So the graph is V-shaped with the vertex at the origin.
The f(x) = - |x| +4 has two important caracteristics:
1. The minus before the |x| reflects the function in the x-axis. So it will still be V-shaped but instead but refected in the x-axis.
2. The +4 moves the function vertically 4 units upwards.
So the graph of f(x) = - |x| +4 will be V-shaped, reflected in the x-axis and moved 4 units upwards.
Attached you can find the graph