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3 years ago

8

PLEASE can someone explain why The exact value of sec ( π/6) is 2 /√ 3 ??

1 answer:

Umnica [9.8K]3 years ago

3 0

$\bf sec\left( \frac{\pi }{6} \right)\qquad recall\to sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus
\\\\
sec\left( \frac{\pi }{6}\right)\iff \cfrac{1}{cos\left( \frac{\pi }{6}\right)}
\\\\\\
\textit{check your Unit Circle for what the }cos\left( \frac{\pi }{6}\right)\ is
\\\\\\
\cfrac{1}{\frac{\sqrt{3}}{2}}\implies \cfrac{\frac{1}{1}}{\frac{\sqrt{3}}{2}}\implies 
\cfrac{1}{1}\cdot \cfrac{2}{\sqrt{3}}\implies \cfrac{2}{\sqrt{3}}$

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