Answer:
Width = 44 yards
Length = 171 yards
Step-by-step explanation:
Given:
<em>Perimeter of the rectangular field = 430 yards.</em>
Let:
<em>The length of the field be L</em>
<em>The width of the field be W.</em>
From the question:
<em>The length of the field is 5yards less than quadruple the width. This implies that;</em>
L = 4W - 5
But.
Perimeter (P) of a rectangle is given by:
P = 2(L + W) ---------------(i)
Substitute the values of P = 430, L = 4W - 5 and W into equation (i) as follows;
430 = 2(4W - 5 + W)
430 = 2(5W - 5)
430 = 10W - 10
10W = 430 + 10
10W = 440
Divide both sides by 10
W = 44
Therefore, the width of the field is 44 yards.
Remember that,
L = 4W - 5
[Now substitute W = 44]
L = 4(44) - 5
L = 176 - 5
L = 171
Therefore, the length of the field is 171 yards
Answer:
one more would be 56
one less would be 54
ten more would 65
ten less would be 45
Step-by-step explanation:
add one more to 55 to get 56
subtract one from 55 to get 54
add ten more to 55 to get 65
subtract ten from 55 to get 45
Answer:
6 and 7
Step-by-step explanation:
is aprox
6.7082039324993690892275210061938287063218550788345771728126917362...
so it's between 6 and 7
The answer is 193.77 because 239.64-45.87 is 193.77.
4. Supplementary angles together make a straight line (two right angles). So BOE is supplementary to BOC
Answer: ∠BOE
5. Distance and midpoint between (4,-2), (6,8)
midpoint
Answer: distance 2√26, midpoint (5, 3)
6.That's a rectangle oriented parallel to the axes, width parallel to the x axis of 7 - -3 = 10 and length along y of 1 - - 4 = 5, so an area of 10(5)=50
Answer: 50
