The equation for the line passing through point A and perpendicular to AB will be y-0.5x=6, the gradient of line AB is -2, and the gradient of a line perpendicular to AB is 0.5.
<h3 /><h3>What is the slope or gradient?</h3>
A numerical assessment of a line's angle relative to the ground is known as the slope.
Given data;
m₁ is the slope of line AB
m₂ is the slope of a line perpendicular to AB
The coordinate points are,
A,(x₁,y₁)= (0, 6)
B,(x₂,y₂)=(3, 0).
The gradient of line AB;
The slope of the lines has a perpendicular relation is -1;
m₁ × m₂ = -1
(-2) × m₂ = -1
m₂ = 1/2
m₂ = 0.5
The equation of the line passing through point A and perpendicular to AB;
(y - y₁) = m₂(x-x₁)
(y-6)=0.5(x-0)
y-6 = 0.5 x
y-0.5x=6
Hence, the gradient of line AB, the gradient of a line perpendicular to AB, and the equation of the line passing through point A and perpendicular to AB will be -2,0.5 and y-0.5x=6.
To learn more about the slope, refer to the link;
brainly.com/question/3605446
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10x100=1,000 because it is ten hundreds so 1,000 is your answer
<em>25 different ways </em>( the answer )
All you have to do is multiple the number by itself
or
<em>Example : </em>
6 backpacks and 3 pencils
6 times 3
18 different combinations :)
Answer:
7x when x=2=<em>7</em><em>×</em><em>2</em><em>=</em><em>1</em><em>4</em><em> </em><em>is</em><em> </em><em>your</em><em> </em><em>answer</em>
Given:
The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).
To find:
The perimeter of quadrilateral ABCD.
Solution:
Distance formula:
Using the distance formula, we get
Similarly,
And,
Now, the perimeter of the quadrilateral ABCD is:
Therefore, the perimeter of the quadrilateral ABCD is 20 units.