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pantera1 [17]
3 years ago
14

PLSSSSSSSSSSSSS HELp VERY URGENT The graph of F(x), shown below, resembles the graph of G(x) = x^2, but it has been stretched so

mewhat and shifted. Which of the following could be the equation of F(x)?

Mathematics
1 answer:
netineya [11]3 years ago
3 0

Answer:

Option B

Step-by-step explanation:

Function 'g' is,

g(x) = x²

Since, leading coefficient of this function is positive, parabola is opening upwards.

From the graph attached,

Function 'f' is opening upwards leading coefficient of the function will be positive.

Since, the graph of function 'f' is vertically stretched, equation will be in the form of f(x) = kx²

Here, k > 1

Since, function 'f' is formed by shifting the graph of function 'g' by 1 unit upwards,

f(x) = g(x) + 1

Combining all these properties, equation of the function 'f' should be,

f(x) = 4x² + 1

Option B will be the correct option.

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On a cold January day, Mavis noticed that the temperature dropped 21 degrees over the course of the day to 9 degrees Celcius. Wr
uranmaximum [27]

Answer:

-9 + 21 = t t = 12°C.

Step-by-step explanation:

For this problem lets have t be equal to the original temperature in the beginning of the day. The equation -9 + 21 = t represents this situation because it states that if we add the degrees that dropped to the current degrees  it will give us our original degrees. Solve. -9 + 21 = t (Simply add -9 + 21) -9 + 21 = (+12) 12 = t So, the original degrees in the beginning of the day was 12°C.

3 0
3 years ago
Help me please im in a rush
Solnce55 [7]

Answer:

a.1

b. 17

Step-by-step explanation:

So the | | around an equation makes it an absolute value which can be defined as the "distance from zero" or in other words, if a value is positive, it stays positive, and if a value is negative, it becomes positive.

|-8 + 9| = |1| = 1

|-8| + 9 = 8 + 9 = 17

7 0
2 years ago
Prove that if a and b are integers, then a^2-4b egal or non-egal 2
Lera25 [3.4K]

Answer:

tex]a^2 - 4b \neq 2[/tex]

Step-by-step explanation:

We are given that a and b are integers, then we need to show that a^2 - 4b \neq 2

Let  a^2 - 4b = 2

If a is an even integer, then it can be written as a = 2c, then,

a^2 - 4b = 2\\(2c)^2 - 4b =2\\4(c^2 -b) = 2\\(c^2 -b) =\frac{1}{2}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

If a is an odd integer, then it can be written as a = 2c+1, then,

a^2 - 4b = 2\\(2c+1)^2 - 4b =2\\4(c^2+c-b) = 2\\(c^2+c-b) =\frac{1}{4}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

Thus, our assumption was wrong and a^2 - 4b \neq 2.

7 0
3 years ago
Need help answering these questions please.
Kisachek [45]
$12.50 because you would divide 50 and 4
3 0
3 years ago
What kind of Function best models the Data in the table?
Vikki [24]

Answer:

a) linear

Step-by-step explanation:

Linear keeps a steady pace throughout the function. in the graph, the function is decreasing by 0.5

8 0
3 years ago
Read 2 more answers
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