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3 years ago

I need help right now this due today(you have been in this situation).

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Answer:

7.62

Step-by-step explanation:

We can draw another point at (-3, -4) named C to get a right-angled triangle.

AC = 2 (by counting)

BC = 7 (by counting)

Using Pythagoras Theorem,

$AC^{2} +BC^{2} =AB^{2}$

$2^2+7^2=AB^2$

$4+49=AB^2$

$AB^2=58$

$AB=\sqrt{58} = 7.62$ (nearest hundredth)

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12% of what number is 42?

Andreyy89

Answer:

350

Step-by-step explanation:

12% = 0.12

42 / 0.12 = 350

3 0

4 years ago

Which pair of lines is parallel? A. y=4x+1 and y+4=5 B. y=-2+x and 2y-2x=-2 C. y=1/4x + 2 and y-2=1/2x D. y=1/5x+1 and 5y+x= 10

sdas [7]

Answer:

B. y=-2+x and 2y-2x=-2

Step-by-step explanation:

Two lines are parallel if they have the same slope.

The equation 0of a line is tipically written as y=mx + b, where 'm' represents the slope and 'b' the y-intercept.

Let's evaluate each of the options:

A. y=4x+1 and y+4x=5

Writing the equations in the slope-intercept form, we get:

y=4x+1 → m=4

y=5-4x → m=-4

Given that they have different slopes, they are not parallel.

B. y=-2+x and 2y-2x=-2

Writing the equations in the slope-intercept form, we get:

y=-2+x → m=1

y=-1 + x → m=1

Given that the equations have the same slope, they are parallel.

C. y=1/4x + 2 and y-2=1/2x

Writing the equations in the slope-intercept form, we get:

y=1/4x + 2 → m=1/4

y=1/2x+2 → m=1/2

Given that they have different slopes, they are not parallel.

D. y=1/5x+1 and 5y+x= 10

Writing the equations in the slope-intercept form, we get:

y=1/5x+1 → m=1/5

5y+x= 10 → y=2 - 1/5x → m=-1/5

Given that they have different slopes, they are not parallel.

4 0

3 years ago

What are the points of discontinutity y=(x-3)/x^2-12x+27

madreJ [45]

Answer:

$(3, -\frac{1}{6})$

Step-by-step explanation:

We can rewrite the equation as

$y = \frac{x - 3}{(x - 3)(x - 9)}$

Notice that we have $x - 3$ in both the numerator and the denominator, so it looks like we can divide it out. However, what if $x - 3$ is $0$ ? Then we would have $y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}$ , which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for $x = 3$ , but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at $x = 3$ . In the simplified version of the function, if we plug in $x = 3$ , we get

$y = \frac{1}{((3) - 9)} = -\frac{1}{6}$

So the point $(3, -\frac{1}{6})$ is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at $x = 9$ (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of $x$