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ad-work [718]
2 years ago
9

Susan made 2 identical necklaces, each having beads and a pendent. The total cost of the beads and pendents for both necklaces w

as $9.80. If the beads cost a total of 3.40, how much did each pendant cost?
Mathematics
2 answers:
Charra [1.4K]2 years ago
7 0

Step-by-step explanation:

$ 3.15 each pendents .......

pogonyaev2 years ago
5 0
$3.15 each pendent.
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In a right triangle, the side opposite a 33 degree angle is 17 units. What is the length of the side adjacent to that angle to t
AnnyKZ [126]

Answer:

The length of the side adjacent to that angle  is 26 units

Step-by-step explanation:

We are given

In a right triangle, the side opposite a 33 degree angle is 17 units

Firstly, we will draw diagram

we can use trig

cot(33)=\frac{x}{17}

now, we can solve for x

x=17\times cot(33)

x=26.177

So,

The length of the side adjacent to that angle  is 26 units

6 0
3 years ago
Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t
Kobotan [32]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

here:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Therefore;

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

3 0
2 years ago
Write the terms a 1a1​, a 2a2​, a 3a3​, and a 4a4 of the following sequence. If the sequence appears to​ converge, make a conjec
Arturiano [62]

Answer:

Step-by-step explanation:

WE are given that a_n = \frac{(-1)^{n+1}}{5n-4}. Then, to now the first for terms, we must replace n by 1,2,3,4 respectively. Then

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a_2 = \frac{(-1)^3}{5(2)-4} = \frac{-1}{6}

a_3 = \frac{(-1)^4}{5(3)-4} = \frac{1}{11}= 1

a_4 = \frac{(-1)^5}{5(4)-4} = \frac{-1}{16}= 1

Note that as n increase, a_n gets closer to 0. So, the limit of this sequence is 0.

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The bottom of a rectangular swimming pool has a perimeter of 62 meters. Its area is 220 square meters. What are the dimensions o
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Answer:

13640cubicmeter........

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