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2 years ago

9

Susan made 2 identical necklaces, each having beads and a pendent. The total cost of the beads and pendents for both necklaces w

as $9.80. If the beads cost a total of 3.40, how much did each pendant cost?

2 answers:

Charra [1.4K]2 years ago

7 0

Step-by-step explanation:

$ 3.15 each pendents .......

pogonyaev2 years ago

5 0

$3.15 each pendent.

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Can someone help me with this?

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Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

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Now,

$Sum = \frac{a( {r}^{n} - 1) }{(r - 1)} \\$

So,

$\frac{a( {r}^{n} - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{2} = 728 \\ {3}^{n} - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n} = 729 \\ {3}^{n} = {3}^{6} \\ \boxed{ n = 6}$

Therefore, number of terms is 6

6 is the right answer.

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Answer:

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Step-by-step explanation:

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