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Vlad [161]
3 years ago
6

What is the range of the fucntion,(6,5)(8,-3)(10,-8)(12,7)

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

5,-3,-8,7 are the range of the function

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Find (fof)(3)<br> f(x) = x^2 - x<br><br> A. 30<br> B. 6<br> C. 33<br> D. -6
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Sub x=3 into ((x^2)-x)^2 - (x^2 - x) = 30. So the answer is A.
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Are the following lines parallel, perpendicular, or neither?
natta225 [31]

Answer:

Perpendicular

Step-by-step explanation:

Parallel lines mean lines that have same slope but since both equations have different slopes which you can check by looking at m-value in y = mx + b. In this case m1 or first slope is -4/3 and m2 or second slope is 3/4.

Perpendicular means that both lines are reciprocal to each other. This means the perpendicular condition is or satisfies \displaystyle \large{m_1m_2 = -1 \longrightarrow m_1 = -\frac{1}{m_2} \longrightarrow m_2 = -\frac{1}{m_1}}

We have m1 = -4/3 and m2 = 3/4.

Therefore, -4/3 * 3/4 = -1 thus both lines are perpendicular to each other as it satisfies m1m2 = -1 condition.

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HELP!! PLEASE!! NEED DONE ASAP I WILL GIVE 100 POINTS AND MORE IF YOU CAN GET ALL 3 QUESTIONS DONE!! THANK YOU!! I WILL ALSO MAR
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Answer:

I answered the questions but that formatting is very confusing and discourages anyone for trying to answer.

The last question is confusing. If I got it wrong, tell me. I will try to answer in the comment section then.

Step-by-step explanation:

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet?

$\text{tan}\theta=\frac{h_{A}}{30} \Rightarrow h_{A}=\text{tan}73\º \cdot 30 \Rightarrow h_{A}\approx 98.12 \text{ feet}$

$\text{tan}\theta=\frac{h_{B}}{35} \Rightarrow h_{B}=\text{tan}73\º \cdot 35 \Rightarrow h_{B}\approx 114.47 \text{ feet}$

\text{Difference} \approx 16.35

Building B is around 16.35 feet taller than building A.

A Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°?

$\text{sin}(y)=\frac{a}{6} $

$\text{tan}(y)=\frac{a}{b} $

a is the opposite side; 6 is the hypotenuse; b is the adjacent side.

Therefore,

$\text{cos}(y)=\frac{b}{6} $

If sin f° = eight ninths and the measure of segment YW is 24 units, what is the measure of segment YX? triangle XYW in which angle W is a right angle, angle X measure f degrees, and angle Y measures d degrees.

This seems a bit confusing. The angles don't match. We have 90\º+62\º +21\º \approx 173\º

\text{sin}(f)=0.888...

f \approx 62\º

YX is the hypotenuse of the right triangle.

$\text{cos}(21\º)=\frac{24}{YX} $

YX \approx 25.7

Considering f \approx 69\º

$\text{sin}(69\º)\approx\frac{24}{YX} $

YX \approx 25.7

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