All categories

3 years ago

Thinking about 1/4 why is 1/4 equal a quarter and a reference to a dollar

Mathematics

1 answer:

miskamm [114]3 years ago

7 0

Answer:

because 4 quarters make a dollar

Step-by-step explanation:

You might be interested in

Which inequality represents this sentence?

butalik [34]

A because D is less than or equal to, C is saying that 9 is bigger than 12 and B is incorrect because the sign is going to point towards the bigger number

4 0

3 years ago

Read 2 more answers

If x^2+2=3^2/3+3^-2/3 then prove that 3x^3+9x-8=0

gregori [183]

Answer:

See below.

Step-by-step explanation:

x^2 + 2 = 3^2/3 + 3^-2/3

x^2 = 3^2/3 + 3^-2/3 - 2

x = √(3^2/3 + 3^-2/3 - 2)

x = 0.748888296

Substitute for x in 3x^3 + 9x - 8:

3( 0.748888296)^3 + 9( 0.748888296) - 8 = 0.

So it is proved.

6 0

3 years ago

Read 2 more answers

How many milliliters are in 30 liters? 300 3,000 30,000 300,000

Alborosie

Answer:

30000 Milliliters

Step-by-step explanation:

multiply the volume value by 1000

30 x 1000 = 30000

Brainliest if this was helpful. Thanks!

3 0

3 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

3 years ago

How to solve 5(x+2)(x-2)

nevsk [136]

The answer is: 5x^2-20

7 0

3 years ago