Given two points (x₁,y₁) and (x₂,y₂) the midpoint would be:
M=((x₁+x₂)/2 , (y₁+y₂)/2)
In this case, the points would be: (1,2) and (1,-5); therefore:
M=((1+1)/2 , (2-5)/2)=(2/2,-3/2)=(1, -3/2)
<span>Answer: B) (1,-3/2)</span>
Hahah the title but I would help but I can’t
Answer:
145/2
Step-by-step explanation:
d=[2x+1-x] = [5x+1 -(2x+1)]
x+1=3x
x-3x=-1
-2x=-1
x=1/2
therefore first term is 1/2
second term is 2(1/2)+1= 2
common difference d is 2-1/2=3/2
sum of first n terms is n/2 [2a+(n-1)d] where n=10
sum of first 10 terms= 10/2[2×1/2+(10-1)3/2]
=5[1+(9)3/2] =5[1+27/2] = 5[29/2] =145/2
Answer:
50
Step-by-step explanation:
add
9 + 1 = 10
multiply
10 * 5 = 50
Answer: 50
