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iogann1982 [59]

3 years ago

14

I need help with this question

1 answer:

pishuonlain [190]3 years ago

6 0

Answer:

1 <—5⁰

25<—5²

1/25<—5-²

5<—5¹

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I need help I don’t get this at all

dolphi86 [110]

Answer:

Step-by-step explanation:

function

5 0

3 years ago

Write the first four terms of the sequence. rule start at 5 1/2, add 1 1/5

Hitman42 [59]

Answer:

$5\frac{1}{2},6\frac{7}{10},7\frac{9}{10},9\frac{1}{10}$

Step-by-step explanation:

The first term of the sequence is

$a_1=5\frac{1}{2}$

To find the second term add $1\frac{1}{5}$ to the first term;

$a_2=5\frac{1}{2}+1\frac{1}{5}=6\frac{7}{10}$

To find the third term add $1\frac{1}{5}$ to the second term;

$a_3=6\frac{7}{10}+1\frac{1}{5}=7\frac{9}{10}$

To find the fourth term add $1\frac{1}{5}$ to the third term;

$a_4=7\frac{9}{10}+1\frac{1}{5}=9\frac{1}{10}$

The first four terms are

$5\frac{1}{2},6\frac{7}{10},7\frac{9}{10},9\frac{1}{10}$

7 0

2 years ago

Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.

Mkey [24]

Answer:

$1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}$

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

$e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}$

Simplification takes place in the following manner:

a)

$(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}$

b)

$(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}$

c)

$(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8$

d)

$(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}$

4 0

3 years ago

If h(x) is the inverse of f(x), what is the value of h(f(x))?

Viktor [21]

The value of h(f(x)) would just be x. That is the line y = x which is the line that functions are reflected in to find the inverse.

4 0

2 years ago

Read 2 more answers

F(x) = -2x^5 + x^4 + x^2 -2; find f(-3) and f(4)

Alekssandra [29.7K]

Answer:

f(-3) = 574

f(4) = -1778

Step-by-step explanation:

$f(x) = -2x^5 + x^4 + x^2 -2$

$f(-3) = -2(-3)^5 + (-3)^4 + (-3)^2 -2$

$\implies f(-3) = -2(-243) + 81 + 9 -2$

$\implies f(-3) = 486 + 81 + 9 -2$

$\implies f(-3) = 574$

$f(4) = -2(4)^5 + (4)^4 + (4)^2 -2$

$\implies f(4) = -2(1024) + 256 + 16 -2$

$\implies f(4) = -2048 + 256 + 16 -2$

$\implies f(4) =-1778$

8 0

2 years ago