The value of x for the given equation (x + 50)/2 = 13x is 2.
According to the given question.
We have an equation (x + 50)/2 = 13x, which represents when two tutoring services with different rate plans charge the same fees for a session of x hours.
So, we have to solve the given equation (x + 50)/2 = 13x for x.
Therefore,
x + 50 = 2(13x)
⇒ x + 50 = 26x
⇒ 26x - x = 50
⇒ 25x = 50
⇒ x = 50/25
⇒ x = 2
Hence, the value of x for the given equation (x + 50)/2 = 13x is 2.
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The standard deviation of the average age of a breed of dog is said to be 3.69.
<h3>What is the standard deviation about?</h3>
Note that we take:
- x = dog age has mean 19.5
- Unknown standard deviation.
Hence:
z = (x - mean) /SD is distributed N (0,1) - mean o standard deviation 1 (standard normal)
Since 20% of dogs are known to be older than 22.6 years:
So 22.6 years is said to be 80th percentile,
Since z matching to 80th percentile (using the standard normal table) s is <em>0.84.</em>
Then one need to plug z, x which is = 22.6
mean = 19.5 into the stated z equation:
Hence,
0.84 = (22.6 - 19.5)/SD
SD = (22.6 - 19.5)/0.84
= 3.69
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The probability of choosing a puppy that is female and white from the given sample we have is; 25%
<h3>How to solve conditional probability?</h3>
The question asks for the probability that Ruby will randomly choose a puppy that is female and white. This is not mutually exclusive events or joint.
White female = 8 - (3 + 1 + 2)
White Female = 2 puppies
Mixed colored females = 3
White male = 1
Mixed colored male = 2
Total number of puppies = 8
Thus, the probability of choosing a puppy that is female and white is;
P(choosing a female puppy) = 2/8 = 1/4 = 25%
Complete question is;
Rubys dog has 8 puppies. the puppies include white females, 3 mixed color females, 1 white male, and 2 mixed color males. ruby wants to keep one puppy.what is the probability that she randomly chooses a puppy that is female and white
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