The half life of the substance is 6.92 days.
<h3>What is the Half life ?</h3>
Half life can be defined as the time required to reduce the concentration to half of its initial value.
Here the equation given is

The concentration will reduce to half therefore

so,

ln 0.5 = - 0.1001 * t(1/2)
-0.693 = -.1001 * t(1/2)
t(1/2) = 6.92 days.
Therefore the half life of the substance is 6.92 days.
To know more about Half Life
brainly.com/question/24710827
#SPJ1
C= -1 because when you add 38 to the other side you are left with -75c=75 then divide by -75 and you are left with -1
One way in which to do this problem would involve subtracting 5 from 7 (result: 2) and then subtracting 3/5 from 8/9.
To subtract 3/5 from 8/9, you'd need to find the lowest common denominator (LCD) of 3/5 and 8/9, convert both fractions to have this LCD, and then subtract.
The LCD is (5)(9)=45. Then 8/9 and 3/5 become 40/45 and 27/45.
Subtracting 27/45 from 40/45 results in the fraction 13/45.
Then the full solution is 2 13/45.
You could also do this problem by converting 7 8/9 and 5 3/5 into improper fractions:
71/9 - 28/5. Again, the LCD is 45. Can you rewrite both fractions with 45 as the common denominator and then perform the subtraction?
Answer:
its the 3rd Graph
Step-by-step explanation:
-1 15
0 18
1 20
2 21