Answer:
Required Probability = 0.97062
Step-by-step explanation:
We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.
Let X = weight of the newborn baby, so X ~ N(
)
The standard normal z distribution is given by;
Z = 
~ N(0,1)
Now, probability that the weight will be less than 5026 grams = P(X < 5026)
P(X < 5026) = P( < 
) = P(Z < 1.89) = 0.97062
Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .
Answer:
Option C is correct
P(A or B) = 0.65
Step-by-step explanation:
<u>Given:
</u>
P(A) =0.5
P(B)=0.30
P(A and B) =0.15
( The probability of the happening of both independent events will be there product) P( A and B ) =P(A).P(B)
<u>Solution:</u>
To find the probability of the Happening of event A either event B we will use the following formula
P(A or B) = P(A) + P(B)-P(A and B)
= 0.5 + 0.3 - 0.15
=0.65
Answer:
See attached image for the drawing of the first four trees (circled in green)
The patterns is:
x = 2+3n and y= 3+2n
Position of 7th tree is: (20,15) (circled in orange in the image)
Step-by-step explanation:
Starting at the location (2,3) the next x and y positions are given by:
x = 2+3n since the horizontal position needs to be increased by 3 units on each iteration,
and y= 3+2n since the vertical position needs to be increased by 2 units on each iteration
being n= 1 through 6 (to account for the next 6 trees that need to be planted)
With such pattern, the location of the seventh tree would be:
x = 2 + 3*6 =2 + 18 = 20
y = 3 + 2*6 = 3 + 12 = 15
That is, the point (20,15) on the plane.
Also see attached image.
Answer:
C, 33 1/3%
Step-by-step explanation:
Because there are only two even number that follow this rule: 2<x≥6, and since there are only 6 possible outcomes, the probabilty is 2/6, which is 1/3. In a percent form, this is 100%*2/3, or 33 1/3%.
