-8 (is less than or equal to) x ( which is less than) 3
Or [-8,3)
H + 2 divided by 4
Please mark as brainliest!
Solution
The 1st term = -3
15th term = 53
15th term = a + d(n-1)
53 = -3 + d(15- 1) [Here n = 15)
53 + 3 = d(14)
14d = 56
d = 4
The common difference is 4.
Answer:
$77,886
Step-by-step explanation:
We solve this question by proportions, using a rule of three.
The table states that:
$201.6 in 2006 is worth $232.957 in 2013.
We want to find:
The value of $90,000 in 2013 in 2006:
$201.6 - $232.957
x - $90000
Applying cross multiplication
$77,886 is the answer
Answer:
The percentage increase in Jayana's postcard collection is 15%
Step-by-step explanation:
Jayana had 20 postcards last year
With 3 more postcards this year
From the given equation Quantity = Percent x Whole
Here;
Let P = Percent/100%
Quantity = Increment in postcard = 3 postcards
Whole = The total postcards from last year = 20 postcards
Hence,
3 postcards = P x 20 postcards
P = 3/20 = 0.15
Recall P = Percent/100%
∴ Percent = P x 100% = 0.15 x 100% = 15%
The percentage increase in Jayana's postcard collection is 15%
