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kow [346]
3 years ago
5

What is -3(2m-5)=1/2(-12m+30)

Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0
-6m+15=-6m+15 !!!!!!!!!!
LekaFEV [45]3 years ago
5 0

Answer:

answer is 0

Step-by-step explanation:

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Write an equation for the nth term of the arithmetic sequence 22, 15, 8, 1,.
DaniilM [7]

Answer:

aₙ = 7n +29

Step-by-step explanation:

  • Arithmetic sequence                

                           22 ; 15 ; 8; 1;........aₙ

  • the nth term

                 aₙ = -7n +29

8 0
3 years ago
Given f(x)=x-10 . what is f(-7)?
Tomtit [17]
F(-7) = -7 - 10

f(-7) = -17


Hope I helped!

Let me know if you need anything else!

<span>~ Zoe (Rank:'Genius')</span>
8 0
3 years ago
Help: I am a number between 60 and 100. My ones digit is six less than my tens digit. I am a prime number.
Reptile [31]

Answer:

Let's name the digit:

x- ones digit

y - tens digit

we know that x=y-2.

Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).

So the possibilities with x=y-2:

64

75

86

97

Out of those 64 and 86 are even, so they can't be prime.

75 has 5 in its ones number: it's divisible by 5.

so the correct answer is 97.

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
Read 2 more answers
Use the method of reduction of order to find a second solution to t^2y' + 3ty' – 3y = 0, t&gt; 0 Given yı(t) = t y2(t) = Preview
Anestetic [448]

Let y_2(t)=tv(t). Then

{y_2}'=tv'+v

{y_2}''=tv''+2v'

and substituting these into the ODE gives

t^2(tv''+2v')+3t(tv'+v)-3tv=0

t^3v''+5t^2v'=0

tv''+5v'=0

Let u(t)=v'(t), so that u'(t)=v''(t). Then the ODE is linear in u, with

tu'+5u=0

Multiply both sides by t^4, so that the left side can be condensed as the derivative of a product:

t^5u'+5t^4u=(t^5u)'=0

Integrating both sides and solving for u(t) gives

t^5u=C\implies u=Ct^{-5}

Integrate again to solve for v(t):

v=C_1t^{-6}+C_2

and finally, solve for y_2(t) by multiplying both sides by t:

tv=y_2=C_1t^{-5}+C_2t

y_1(t)=t already accounts for the t term in this solution, so the other independent solution is y_2(t)=t^{-5}.

6 0
4 years ago
What intervals would you use to determine where
Leona [35]

Answer: B on e2020

Step-by-step explanation:

i just did it

5 0
4 years ago
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