Let the dimensions be x and y
Given that the area is 40m²
xy = 40 ----------------- (1)
Given that the perimeter is 26
2(x + y) = 26
x + y = 13
x = 13 - y ---------------- Sub into (1)
(13 - y)y = 40
13y - y² = 40
y² - 13y + 40 = 0
(y - 8)(y - 5) = =
y = 8 or y = 5
The dimensions are 8 meters and 5 meters
The classes could each have proportions of 5 boys to 6 girls, but they don’t necessarily have to be exactly 5 to 6. The number could 5 to 6 for one class, but it could also be 10 to 12 for another class, since 10 to 12 is a scale factor of 5 to 6.
Answer:
See explanation
Step-by-step explanation:
<u><em>1st photo:</em></u>
x = 
= 15
x =
<u><em>2nd photo:</em></u>
(a) GEH ~ FGH ~ FEG
<em>similar triangles, use similar corners in the right order</em>
(b) 
AND 
<em>similar triangles, use similar sides in proportion</em>
<em />
<u><em>3rd photo:</em></u>
x = 4.5 or 4 1/2
<em>2x = 9</em>
<em>x = 4.5 or 4 1/2</em>
<em />
<u><em>4th photo:</em></u>
Length of string = 118.2 ft
<em>sin(40) = 76/x</em>
<em>x = 76/sin(40) = 118.2</em>
Answer:
C is the answer.
Step-by-step explanation:
Answer:
x = price of balcony tickets = $7
y = price of orchestra tickets = $21
Step-by-step explanation:
Let
x = price of balcony tickets
y = price of orchestra tickets
y = 3x (1)
148y + 76x = 3,640 (2)
Substitute y = 3x into (2)
148y + 76x = 3,640 (2)
148(3x) + 76x = 3,640
444x + 76x = 3,640
520x = 3,640
x = 3,640/520
x = 7
Substitute x = 7 into (1)
y = 3x (1)
y = 3(7)
y = 21
x = price of balcony tickets = $7
y = price of orchestra tickets = $21
