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tiny-mole [99]
3 years ago
9

Two brothers went shopping at a back to school sale where all shirts and shorts were the same price. The younger brother spent $

145 on 7 new shirts and 7 pairs of shorts. The older brother purchased 6 new shirts and and 7 pairs of shorts and paid a total of $125 How much did one shirt cost?
Mathematics
1 answer:
Lana71 [14]3 years ago
5 0
145÷14=10.357142857142857143
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a trail is 5 miles long. carlos walks 2/3 of the trail and runs the rest. how many miles does carlos walk?
lana [24]

Answer:

as 1 mile = 1.609 km

so 5miles = 8.045 km

so 2/3 of the trail = 2/3 × 8.045 = 5.3633333 (ans)

Hope it helps

8 0
3 years ago
What is the equation of a line that is perpendicular to this line and goes through the
-Dominant- [34]

Answer:

x + 3y + 9 = 0

Step-by-step explanation:

y=3x + 2

Coefficient of x = 3

Gradient (m) of line y= 3x + 2 is 3

Since the line passing through point

(3,-4) is perpendicular to line y=3x + 2

hence gradient (m) of the line is -1/3;

And hence it equation is given as;

y - y1 = m(x - x1)

y - (-4) = -1/3(x - 3)

multiplying through by 3;

3 × y + 3 × 4 = 3 × -1/3(x - 3)

3y + 12 = -1(x - 3)

3y + 12 = -x + 3

x + 3y + 12 - 3 = 0

x + 3y + 9 = 0

5 0
3 years ago
Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0
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Answer:

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3 years ago
Evaluate 1/2m - 2/3n when m = 3 and n = 8.
Anika [276]

Answer:

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6

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6

7 0
3 years ago
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