Does the question have a photo attached on your screen because it sounds like the image you included is not completed
Answer:
(x = -6), (y = -6)
(-6,-6)
Step-by-step explanation:
X=-6
3x - 2y = -6
3(-6) - 2y = -6
-18 - 2y = -6
What you do to one side, you do to the other. And when you take it over to the other side, you'll have to turn -18 into a positive 18.
-2y = 18 - 6
-2y = 12
Divide both sides by -2
y = -6
Answer:C
Step-by-step explanation:
Looking at number line, the function value always range from positive value from 0 to negative numbers to -1
Hello,
y=2x+5
==========
(y-5)=2(x-0)
<h2>
Hello!</h2>
The answer is:
The second option,
Zackery, because AB=BC
<h2>Why?</h2>
To identify which type of triangle is the triangle formed by the given points, first, we need to calculate the distance between the points.
So, finding the distances we have:
From A to B: (2,3) and (4,4)
![distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(4-2)^{2} +(4-3)^{2}}=\sqrt{2^{2} +1^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units](https://tex.z-dn.net/?f=distance%3D%5Csqrt%7B%28x_2-x_1%29%5E%7B2%7D%20%2B%28y_2-y_1%29%5E%7B2%7D%7D%5C%5C%5C%5Cdistance%3D%5Csqrt%7B%284-2%29%5E%7B2%7D%20%2B%284-3%29%5E%7B2%7D%7D%3D%5Csqrt%7B2%5E%7B2%7D%20%2B1%5E%7B2%7D%20%7D%3D%5Csqrt%7B4%2B1%7D%3D%5Csqrt%7B5%7D%3D2.24units)
From B to C: (4,4) and (6,3)
![distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(6-4)^{2} +(3-4)^{2}}=\sqrt{2^{2} +(-1)^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units](https://tex.z-dn.net/?f=distance%3D%5Csqrt%7B%28x_2-x_1%29%5E%7B2%7D%20%2B%28y_2-y_1%29%5E%7B2%7D%7D%5C%5C%5C%5Cdistance%3D%5Csqrt%7B%286-4%29%5E%7B2%7D%20%2B%283-4%29%5E%7B2%7D%7D%3D%5Csqrt%7B2%5E%7B2%7D%20%2B%28-1%29%5E%7B2%7D%20%7D%3D%5Csqrt%7B4%2B1%7D%3D%5Csqrt%7B5%7D%3D2.24units)
Hence, since the distances AB and BC are equal, the triangle is an isosceles triangle, so the answer is:
Zackery, because AB=BC
Have a nice day!