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dezoksy [38]
3 years ago
5

A robot begins its journey at the origin, point 0, and travels along a straight line path at a constant rate. Fifteen minutes in

to its journey the robot is at A(5, 8) .
(a.) If The robot does not change speed or direction, where will it be 3 hours into its journey (Call this point B)? (B.) The robot continues past point B for a certain period of time until it has traveled an additional 3/4 the distance it traveled in the first 3 hours and stops. i. How long did the robot's entire journey take? ii. What is the robot's final location?
c. What was the distance the robot traveled in the last leg of its journey?
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0
A) Point B(60,96)
B)i. 315 mins (or 5.25 hours [or 5 1/4 hours])
ii. Ended at coordinates (105,168)
C) it travelled a distance of the origin to coordinates (45,72). It travelled 45 in the x direction and 72 in the y direction.

C is confusing question. Assuming that means after it stopped and continued again, the last leg of the journey was just the slope 72/45; or

First find the slope
Slope=rise/run
Slope=8/5
During 15 mins the robot goes at the slope of 8/5.
3 hours is 180 mins.
180/15=12
8/5*12=96/60
Remember!! Slope=rise/run, now UNDO it
96/60 (undo it) becomes point B (60,96)

An additional 3/4 of slope 96/60 is:
(96/4)*3=72
(60/4)*3=45
72/45=3/4 of 96/60
Dividing 72 by 45 and 96 by 60 will yield the same number (therefore the slope is the same therefore that checks that this is correct)
The time is took to do 96/60 was 3 hours, or 180 mins. (180/4)*3=135
The new total time of journey is 180+135=315 mins
Final location is just adding (45,72) and (60,96) to get (105,168)
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The temperature dropped 20 degrees in 10 hours.

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The vertex of ∠ABC is <br> A<br> B <br> C
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Can somebody help me with this problem
soldier1979 [14.2K]
115 degrees because there are 180 degrees in a triangle so let the missing angle in the trinagle be x. Then we have x+75+40=180. Solving for x and subtracting that from 180 (supplementary angles) we get 115 degrees.
4 0
3 years ago
Write an equation in point-slope form of the line that passes through the given point and has the given slope. (3, –8); m = –5
Paraphin [41]

Answer:

y+8=-5(x-3)

Step-by-step explanation:

The formula for point-slope form is y-y1=m(x-x1)

The points for (x1, y1) are (3, -8), meaning that 3 is x1 and -8 is y1.

So, start by writing your equation like this: y--8=m(x-3)

For the equation y--8=m(x-3), the y--8 will change to a + sign because two negatives make a positive, right? So, the equation should now look like this: y+8=m(x-3).

We know that the slope (m) is -5. Plug that into the equation to get this: y+8=-5(x-3)

And there you have it!! The equation is now in point-slope form!!

y+8=-5(x-3) is the final answer!!

Hope that helps you!! Please give me brainliest!!

7 0
2 years ago
An horse gallops 200ft turns and trots 350ft turns again and travels 410ft
bija089 [108]

The area of the triangle formed by his path is 34971.98 ft sq to the nearest hundredth.

<h3>What is the Heron's formula?</h3>

The Heron's formula is given as;

√s(s-a)(s-b)(s-c)

where s is half the perimeter of the triangle

WE have been given that horse gallops 200ft, turns and trots 350ft, turns again and travels 410ft to return to the point he started from.

Perimeter of the triangle is given as = 200 + 350 + 410 = 960 ft

Semi perimeter =  960 ft/ 2 = 480 ft

Area =  √s(s-a)(s-b)(s-c)

Area =  √480 (480 -200)(480 -350)(480 -410)

Area =  √480 (280)(130)(70)

Area =  √480 (2548000)

Area = 34971.98

The area of the triangle formed by his path is 34971.98 ft sq to the nearest hundredth.

Learn more about the Heron's formula;

brainly.com/question/20934807

#SPJ1

The complete question is

A horse gallops 200ft, turns and trots 350ft, turns again and travels 410ft to return to the point he started from. What is the area of the triangle formed by his path? round to the nearest hundredth.

6 0
1 year ago
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