Cylinder has both circles top and bottom.
Answer:
Step-by-step explanation: when h(x) = 10
h(x)= 6-x
h(10)= 6-10
=-4
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Hi there. Actually, the image that you have provided us with is a little bit blurry so, if you can make the image a little bit clearer, then I can help you with this question.
Thanks.
Hello,
3(2m-9+6m)=3m+29-7m
==>3(8m-9)=-4m+29
==>24m+4m=29+27
==>28m=56
==>m=2
Answer B