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Anvisha [2.4K]
3 years ago
8

I need help please can not figure out this problem

Mathematics
1 answer:
enot [183]3 years ago
5 0
1. (2x-3)(x-4)
2x(x) =2x^2
2x(-4)= -8x
-3(x)= -3x
-3(-4)= 12
2x^2 -8x-3x+12= 2x^2 -11x+12

2. (x+2)(x+5)
x^2+5x+2x+10= x^2 +7x+10

3. (3x-1)(x+2)
3x^2 +6x-x-2= 3x^2+5x-2
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A student paid 256.37 Ghana cedis in school fees. how much has he paid to the nearest hundred?​
statuscvo [17]

Answer:

256.4

Step-by-step explanation:

4 0
3 years ago
Solve the absolute value equation,if possible.If there is no solution,explain why. |5x+13|=-7
SOVA2 [1]

Answer:

Step-by-step explanation:

There is nothing you could put into the brackets that will give you a negative answer. We should just graph this to see if that is true or not. Graphs are the last word in this kind of question.

See below.

The graph is the first part:  y = |5x +7|

It is the red graph.

The second line of interest is y = - 7. It is blue.

Do you see that these two graphs do not intersect?

Because they don't, there is no solution. Any marker will accept this explanation and the graph. You should be fine with just this much.

4 0
4 years ago
Which operation could we perform in order to find the number of milliseconds in a year? 60 * 60 * 24 * 7 * 365 1000 * 60 * 60 *
Tom [10]
Use the following abbreviations:
y = year,
d = day,
h = hour,
min = minute,
s = second,
ms = millisecond.

Then
1 \, y = (1 \, y)*(365 \,  \frac{d}{y} )*(24 \,  \frac{h}{d} )*(60 \,  \frac{min}{h} )*(60 \,  \frac{s}{min} )*(1000 \,  \frac{ms}{s} )

Therefore, the correct calculation is
1000 * 60 * 60 * 24 * 365

Answer: 1000 * 60 * 60 * 24 * 365

4 0
3 years ago
Please help!:
My name is Ann [436]
The answer is 2 solution.

#Solution
3x + 12 + 18 = 0 \\3x = - 18 - 12 \\ 3x = - 30 \\ x = - 10
3x + 12 - 18 = 0 \\ 3x = 18 - 12 \\ 3x = 6 \\ x = 2
8 0
4 years ago
Read 2 more answers
Please help, don’t understand. For #14 what would the input of the function be?
Goryan [66]

a)

h(t) , namely "h" variable is being represented in terms of "t".

h = dependent variable, depends on the value of "t", output.

t = independent variable, takes on values freely, input.


b)

\bf \stackrel{\stackrel{h(t)}{t=1.4}}{h(1.4)} = \stackrel{h=12.8}{12.8}~~ \begin{cases} t=1.4~~&\textit{after 1.4 seconds}\\ h=12.8~~&\textit{the ball is 12.8 meters up} \end{cases}


c)

\bf h(2)=-5(2)^2+14(2)+3\implies h(2)=-20+28+3\implies h(2)=11

after 2 seconds, the ball is 11 meters high up.

5 0
3 years ago
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