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3 years ago

Please help, don’t understand. For #14 what would the input of the function be?

Mathematics

1 answer:

Goryan [66]3 years ago

5 0

h(t) , namely "h" variable is being represented in terms of "t".

h = dependent variable, depends on the value of "t", output.

t = independent variable, takes on values freely, input.

$\bf \stackrel{\stackrel{h(t)}{t=1.4}}{h(1.4)} = \stackrel{h=12.8}{12.8}~~ \begin{cases} t=1.4~~&\textit{after 1.4 seconds}\\ h=12.8~~&\textit{the ball is 12.8 meters up} \end{cases}$

$\bf h(2)=-5(2)^2+14(2)+3\implies h(2)=-20+28+3\implies h(2)=11$

after 2 seconds, the ball is 11 meters high up.

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What is the measure of ∠BCD? Enter your answer in the box. ° PLSSS help

denpristay [2]

It seems to be a tilted square, so all angles are the same.
$103 \times 3$
so maybe just multiply by 3 and get 309 since B, C, and D are three angles.
$103 \times 3 = 309$
I might be wrong but, the answer should be 309.

8 0

3 years ago

Help plz for brainliest

zhuklara [117]

Answer:

75 in³

x: 30

y: 20 35

Step-by-step explanation:

v = πr²h / 3

v = 3.14 * 3² * 8 / 3

v = 3.14 * 9 * 8 / 3

v = 75.36 in³

Rounded

v = 75 in³

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x increase by 10 for each step

y increases by 7.5 for each step

x: 0 10 20 30 40

y: 5 12.5 20 27.5 35

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3 years ago

Read 2 more answers

Carrie used 6 lemons to make 24 fluid ounces of lemonade. Carrie is having a big party and needs to make 288 fluid ounces of lem

Anika [276]

Answer:

72 is the answer

6 0

3 years ago

Find the missing side. Need help please. Need explanation, please.

My name is Ann [436]

Answer: x = 4.37 (rounded)

Step-by-step explanation:

Using the tangent rule.

tan = opposite side/ adjacent side.

I recommend Khan Academy for more practice on this topic.

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3 years ago

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The National Collegiate Athletic Association (NCAA) requires colleges to report the graduation rates of their athletes. At one l

nevsk [136]

Answer:

The null hypothesis is $H_0: p = 0.91$ .

The alternate hypothesis is $H_1: p < 0.91$ .

The decision rule is: accept the null hypothesis for $z > -1.645$ , reject the null hypothesis for $z < -1.645$ .

Since $z = -1.79 < -1.645$ , we reject the null hypothesis and accept the alternate hypothesis that that percentage of athletes who graduate is less than for the student population at large.

The p-value for this test is 0.0367. Since this p-value is less than the significance level of $\alpha = 0.05$ , we reject the null hypothesis and accept the alternate hypothesis that that percentage of athletes who graduate is less than for the student population at large.

Step-by-step explanation:

Question a:

Perform the appropriate hypothesis test to determine whether this is significant evidence that the percentage of athletes who graduate is less than for the student population at large:

At the null hypothesis, we test if the proportion is the same as the student population, of 91%. Thus:

$H_0: p = 0.91$

At the alternate hypothesis, we test that the proportion for athletes is less than 91%, that is:

$H_1: p < 0.91$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

Test if the proportion is less at the 0.05 level:

The critical value is z with a p-value of 0.05, that is, z = -1.645. Thus, the decision rule is: accept the null hypothesis for $z > -1.645$ , reject the null hypothesis for $z < -1.645$ .

0.91 is tested at the null hypothesis:

This means that $\mu = 0.91, \sigma = \sqrt{0.91*0.09}$

A sports reporter contacted 152 athletes randomly sampled from that same university and time period and found that 132 of them had graduated within 6 years.

This means that $n = 152, X = \frac{132}{152} = 0.8684$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.8684 - 0.91}{\frac{\sqrt{0.91*0.09}}{\sqrt{152}}}$

$z = -1.79$

Since $z = -1.79 < -1.645$ , we reject the null hypothesis and accept the alternate hypothesis that that percentage of athletes who graduate is less than for the student population at large.

(b) (3 points) Calculate the P-value for this test. Explain how this P-value can be use to test the hypotheses in part (a).

The p-value of the test is the probability of finding a sample proportion of 0.8684 or below. This is the p-value of z = -1.79.

Looking a the z-table, z = -1.79 has a p-value of 0.0367.

8 0

3 years ago