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Sindrei [870]
3 years ago
14

Please guys i really need an answer it is due tommorow i really need help

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0
I think what u would do is multiply the forth thing by 2 and then count how many blocks are in the 5th :)))
You might be interested in
In the U.S thirteen of twenty cans are recycled. What % of cans are recycled?
madam [21]

A percent is how many out of 100.

13/20 is how many out of 100?

You multiply the top and bottom by 5, as 5x20 is 100

13x5 is 65

Therefore, 65 out of every hundred cans, or 65%, are recycled

8 0
4 years ago
a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s
Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

                         P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s^{2}  = sample variance = 97^{2} = 9409

              n = sample of boxes = 15

           \sigma^{2}  = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, \sigma^{2} is ;

P(5.629 < \chi^{2}__1_4 < 26.12) = 0.95  {As the critical value of chi-square at 14

                                         degree of freedom are 5.629 & 26.12}  

P(5.629 < \frac{(n-1)s^{2} }{\sigma^{2} } < 26.12) = 0.95

P( \frac{5.629 }{(n-1)s^{2} } < \frac{1}{\sigma^{2} } < \frac{26.12 }{(n-1)s^{2} } ) = 0.95

P( \frac{(n-1)s^{2} }{26.12 } < \sigma^{2} < \frac{(n-1)s^{2} }{5.629 } ) = 0.95

<u><em>95% confidence interval for</em></u> \sigma^{2} = [ \frac{(n-1)s^{2} }{26.12 } , \frac{(n-1)s^{2} }{5.629 } ]

                                                  = [ \frac{14 \times 9409 }{26.12 } , \frac{14 \times 9409 }{5.629 } ]

                                                  = [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0
4 years ago
Identify the domain of the exponential function shown in the following graph:
NemiM [27]
The domain is the set of values of the x-axys.

As per your description of the function, it goes from negative infinity to positive infinity.
6 0
3 years ago
For which value of x is line L parallel to line M?
ycow [4]

Answer:

x=8

Step-by-step explanation:

5x+10+130=180

5x+140=180

5x=40

x=8

6 0
3 years ago
Read 2 more answers
Evaluate 5^2 + 10 ÷ 2.
Kaylis [27]

Answer:

Step-by-step explanation:

5^2 + 10 ÷ 2

25 + 10 ÷ 2

25 + 5

30

6 0
3 years ago
Read 2 more answers
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