The common factor would be 3 because 3 is the highest multiple of 15 and 9
Answer:
UNIF(2.66,3.33) minutes for all customer types.
Step-by-step explanation:
In the problem above, it was stated that the office arranged its customers into different sections to ensure optimum performance and minimize workload. Furthermore, there was a service time of UNIF(8,10) minutes for everyone. Since there are only three different types of customers, the service time can be estimated as UNIF(8/3,10/3) minutes = UNIF(2.66,3.33) minutes.
Answer:
The equation i.e. used to denote the population after x years is:
P(x) = 490(1 + 0.200 to the power of x
Step-by-step explanation:
This problem could be modeled with the help of a exponential function.
The exponential function is given by:
P(x) = ab to the power of x
where a is the initial value.
and b=1+r where r is the rate of increase or decrease.
Here the initial population of the animals are given by: 490
i.e. a=490
Also, the rate of increase is: 20%
i.e. r=20%
i.e. r=0.20
Hence, the population function i.e. the population of the animals after x years is:
P(x) = 490(1 + 0.200 to the power of x
Answer:
she would save 1.1 extra gallons
Step-by-step explanation:
54 miles to work
30 miles a gallon so 1.8 gallons to get to work
27 miles a gallon so 2 gallons to get to work
30 miles car saves 5.4 miles more each day she drives to work
5.4 X 5 = 27 extra miles so 1.1 gallons she would be saving each work week
