In ΔBCD, the measure of ∠D=90°, the measure of ∠B=8°, and BC = 6.4 feet. Find the length of DB to the nearest tenth of a foot.
2 answers:
You might be interested in
Answer:
A'(-3,0), B'(0,-3) and C'(4,7)
Step-by-step explanation:
We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).
We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.
90° clockwise about the origin
Rule:
Using the rule
The coordinates of A'
The coordinates of B'
The coordinates of C'
Hence, the vertices of image of triangle is given by
A'(-3,0), B'(0,-3) and C'(4,7)
