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Paha777 [63]
3 years ago
8

{60} /\sqrt{5} (in radical form)" alt="\sqrt{60} /\sqrt{5} (in radical form)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
3 0

2\sqrt{3}

------------------------

Steps:

1st write out equation

\frac{\sqrt{60}}{\sqrt{5}} \\

Second write the conjugant and multiply it.

\frac{\sqrt{60}}{\sqrt{5}} * \frac{\sqrt{5} }{\sqrt{5} }

After multiplying you should get,

\frac{10\sqrt{3}}{5}

now after simplifying you should get

2\sqrt{3}

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Step-by-step explanation:

<u>For the Problem 1:</u>

In the first step, Hilda applied the <em>Conmutative Property of Multiplication</em>, because she changed the order of the numbers in the product

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<u>For the Problem 2:</u>

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In the second step, she applied the<em> Associative Property of Addition, </em>because she associated the addition of 17 and 3 and the addition of 29 and 1, to calculate them in groups.

<em />

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