Find the gradients of line a and b
1 answer:
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<span>First year is 30,000.
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.
An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53
S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
S40 = 30,000 * -6.039988712 / -.05 which becomes:
</span>S40 = -181,199.6614 / -.05 which becomes:
S40 = $3,623,993.227
<span>The individual yearly calculations are shown below: </span>
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.
An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53
S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
S40 = 30,000 * -6.039988712 / -.05 which becomes:
</span>S40 = -181,199.6614 / -.05 which becomes:
S40 = $3,623,993.227
<span>The individual yearly calculations are shown below: </span>
Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards
the distance between them is 476 miles, and they met 8.5hrs later
let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs
we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2
thus
solve for "r", to see how fast the cyclist was going
what about the car? well, the car's rate is r + 33.2
the distance between them is 476 miles, and they met 8.5hrs later
let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs
we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2
thus
solve for "r", to see how fast the cyclist was going
what about the car? well, the car's rate is r + 33.2