![\bf \textit{we know the range for }cos\left( \frac{1}{x} \right)\textit{ is }[-1,1]\textit{ therefore} \\\\\\ -1~\ \textless \ ~cos\left( \frac{1}{x} \right)~\ \textless \ ~1\impliedby \textit{multiplying all sides by }x^2 \\\\\\ -1x^2~\ \textless \ ~x^2cos\left( \frac{1}{x} \right)~\ \textless \ ~1x^2\implies -x^2~\ \textless \ ~x^2cos\left( \frac{1}{x} \right)~\ \textless \ ~x^2](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bwe%20know%20the%20range%20for%20%7Dcos%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29%5Ctextit%7B%20is%20%7D%5B-1%2C1%5D%5Ctextit%7B%20therefore%7D%0A%5C%5C%5C%5C%5C%5C%0A-1~%5C%20%5Ctextless%20%5C%20~cos%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29~%5C%20%5Ctextless%20%5C%20~1%5Cimpliedby%20%5Ctextit%7Bmultiplying%20all%20sides%20by%20%7Dx%5E2%0A%5C%5C%5C%5C%5C%5C%0A-1x%5E2~%5C%20%5Ctextless%20%5C%20~x%5E2cos%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29~%5C%20%5Ctextless%20%5C%20~1x%5E2%5Cimplies%20-x%5E2~%5C%20%5Ctextless%20%5C%20~x%5E2cos%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29~%5C%20%5Ctextless%20%5C%20~x%5E2)
if the limit of -x² goes to "something", and the limit of x² goes to the same "something", if their limit coincide, and yet they're bounding the cosine expression, therefore, since the cosine expression is "sandwiched" between -x² and x², then the cosine expression "squeezes in" that little sliver between both -x² and x², and will inevitably go to the same limit.
Answer: 615.44 m^3.
Step-by-step explanation: To find the volume of a cone, you need to multiply the radius, pi, and height. The equation is given below:
π x r^2 x h = V, where π is pi, r is the radius squared, h is the height, and V is the volume.
Now, we need to substitute the values with the information that is given. π ≈ 3.14:
3.14 x 7^2 x 12 ≈ 1846.32.
We are not finished yet! A cone's volume is a third of a cylinder's, so you need to split 1846.32 in 1/3:
1/3 x 1846.32 ≈ 615.44 m^3.
Hope this helps! :)
11/18 is the correct answer:))
Answer:
1.24 kilograms per cubic meter.
Step-by-step explanation:
5x + 1 = 5x + n
n - any real number except 1
Examples:
n = 2
5x + 1 = 5x + 2 <em>subtract 5x from both sides</em>
1 = 2 FALSE -> NO SOLUTION
n = 0
5x + 1 = 5x + 0 <em>subtract 5x from both sdies</em>
1 = 0 FALSE -> NO SOLUTION
n = -4
5x + 1 = 5x + (-4) <em>subtract 5x from both sides</em>
1 = -4 FALSE -> NO SOLUTION