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Softa [21]
3 years ago
14

Caitlin is a highly motivated sales executive for a company that sells business textbooks. She always strives to create personal

relationships with the professors of colleges and universities. When a committee of professors at Bridgeton University was constituted to select a new marketing book, her book was selected. Her amiable relationship with the committee chairman paved the way for this selection. The committee chairman trusts Caitlin and believes that she will meet his expectations. Identify the type of relationship between Caitlin and the committee chairman in this scenario.
A. Relational partnership
B. Functional relationship
C. Internal partnership
D. Solo market transaction
E. Strategic partnership
Business
1 answer:
timurjin [86]3 years ago
7 0

Answer:

A. Relational partnership

Explanation:

Relational partnership - This type of partnership is based on trust and close relationships. In this type of relationship, both parties are open on discussion and always ready to tackle the objection or obstacle by working together.

In every partnership, both parties are trying to get more money but the main focus on this partnership is to get that money for a longer period of time.

Mostly relationship partnership built because of prior relationship but mostly it is happened due to financial necessity.

You might be interested in
Pioneer Systems Inc. has a high degree of formalization. Employees in Pioneer Systems are more likely to: Multiple Choice
g100num [7]

Answer:

The correct answer is letter "D": face morale and motivation problems.

Explanation:

A high degree of formalization will result in reduced creativity as workers are told to behave in a specific way. In such organizations, strategic decision-making often happens only when there is a problem. A highly formalized structure is usually related to reduced motivation and morale issues among employees.

8 0
3 years ago
Alfred lost his 3-year-old camera. It cost him $150 three years ago and had a life expectancy of 6 years. Alfred has actual cash
salantis [7]

Answer:

insurance company will pay $75 to Alfred.

Explanation:

given data

Actual cost of camera = $200

Alfred cost of camera = $150

Life expectancy = 6 years

solution

we get here first Remain life of camera that is

Remain life of camera = 6 years  - 3 years

Remain life of camera = 3 years

and

now we get here current cost of the camera that is

current cost of camera = Alfred cost of camera × (Remain life of camera ÷ Life expectancy)    ........................1

put here value and we get

Current cost of camera = $150   ×   \frac{3}{6}

Current cost of camera = $75

so that insurance company will pay $75 to Alfred.

5 0
3 years ago
Splish Company purchased a computer for $9,920 on January 1, 2019. Straight-line depreciation is used, based on a 5-year life an
BartSMP [9]

Answer:

$2914

Explanation:

The following steps would be taken to determine the answer

1. Calculate depreciation expense given the initial information  

2. calculate the accumulated depreciation by the second year. Accumulated depreciation is sum of depreciation expense

3. subtract the accumulated depreciation from the cost price of the asset. This would give the book value  

4. calculate the depreciation expense using the new information and the book value

Straight line depreciation expense = (Cost of asset - Salvage value) / useful life

($9,920 - $1240) / 5 =  $1736

Accumulated depreciation = 1736 x 2 = $3472

Book value at the beginning of 2021 = 9920 - 3472 = $6448

Depreciation expense in 2021 = (6448 - 620) / 2 = $2914

5 0
3 years ago
Instructions: Please make sure that you show all your work when solving the problems. Feel free to make any assumptions whenever
My name is Ann [436]

Answer:

Explanation:

From the given information:

The current price = \dfrac{Dividend(D_o) \times (1+ Growth  \ rate) }{\text{Cost of capital -Growth rate}}

15 = \dfrac{0.50 \times (1+ Growth rate)}{8\%-Growth rate}

15 \times (8 -Growth \  rate) = 0.50 +(0.50 \times growth  \  rate)

1.20 - (15 \times Growth \ rate) = 0.50 + (0.50 \times growth \ rate)

0.70 = (15 \times growth  \ rate) \\ \\ Growth  \ rate = \dfrac{0.70}{15.50} \\ \\ Growth  \ rate = 0.04516 \\ \\ Growth  \ rate \simeq 4.52\% \\ \\

2. The value of the stock  

Calculate the earnings at the end of  5 years:

Earnings (E_o) \times Dividend \  payout  \ ratio = Dividend (D_o) \\ \\ Earnings (E_o) \times 35\% = \$0.50 \\ \\ Earnings (E_o) =\dfrac{\$0.50}{35\%} \\ \\ = \$1.42857

Earnings (E_5) year \  5  = Earnings (E_o) \times (1 + Growth \ rate)^{no \ of \ years} \\ \\ Earnings (E_5) year \  5  = \$1.42857 \times (1 + 12\%)^5 \\ \\ Earnings (E_5) year \ 5  = \$2.51763

Terminal value year 5 = \dfrac{Earnings (E_5) \times (1+ Growth \ rate)}{Interest \ rate - Growth \ rate}

=\dfrac{\$2.51763\times (1+0.04516)}{8\%-0.04516}

=$75.526

Discount all potential future cash flows as follows to determine the stock's value:

\text{Value of stock today} =\bigg( \sum \limits ^{\text{no of years}}_{year =1} \dfrac{Dividend (D_o) \times 1 +Growth rate ) ^{\text{no of years}}}{(1+ interest rate )^{no\ of\ years} }

+ \dfrac{Terminal\ Value }{(1+interest \ rate )^{no \ of \ years}} \Bigg)

\implies \bigg(\dfrac{\$0.50\times (1 + 12\%)^1) }{(1+ 8\%)^{1} }+ \dfrac{\$0.50\times (1+12\%)^2 }{(1+8\% )^{2}}+ \dfrac{\$0.50\times (1+12\%)^3 }{(1+8\% )^{3}}  + \dfrac{\$0.50\times (1+12\%)^4 }{(1+8\% )^{4}} + \dfrac{\$0.50\times (1+12\%)^5 }{(1+8\% )^{5}} + \dfrac{\$75.526}{(1+8\% )^{5}} \bigg )

\implies \bigg(\dfrac{\$0.5600}{1.0800}+\dfrac{\$0.62720}{1.16640}+\dfrac{\$0.70246}{1.2597}+\dfrac{\$0.78676}{1.3605}+\dfrac{\$0.88117}{1.4693}+ \dfrac{\$75.526}{1.4693} \bigg)

=$ 54.1945

As a result, the analysts value the stock at $54.20, which is below their own estimates.

3. The value of the stock  

Calculate the earnings at the end of  5 years:

Earnings (E_o) \times Dividend payout ratio = Dividend (D_o) \\ \\ Earnings (E_o) \times 35\% = \$0.50 \\ \\ Earnings (E_o) =\dfrac{\$0.50}{35\%}\\ \\ = \$1.42857

Earnings (E_5) year  \ 5  = Earnings (E_o) \times (1 + Growth \ rate)^{no \ of \ years} \\ \\ Earnings (E_5) year  \ 5  = \$1.42857 \times (1 + 12\%)^5 \\ \\ Earnings (E_5) year \  5  = \$2.51763 \\ \\

Terminal value year 5 =\dfrac{Earnings (E_5) \times (1+ Growth \ rate)\times dividend \ payout \ ratio}{Interest \ rate - Growth \ rate}

=\dfrac{\$2.51763\times (1+ 7 \%) \times 20\%}{8\%-7\%}

=$53.8773

Discount all potential cash flows as follows to determine the stock's value:

\text{Value of stock today} =\bigg( \sum \limits ^{\text{no of years}}_{year =1} \dfrac{Dividend (D_o) \times 1 + Growth rate ) ^{\text{no of years}}}{(1+ interest rate )^{no \ of\ years} }+ \dfrac{Terminal \ Value }{(1+interest \ rate )^{no \ of \ years }}   \bigg)

\implies \bigg( \dfrac{\$0.50\times (1 + 12\%)^1) }{(1+ 8\%)^{1} }+ \dfrac{\$0.50\times (1+12\%)^2 }{(1+8\% )^{2}}+ \dfrac{\$0.50\times (1+12\%)^3 }{(1+8\% )^{3}}  + \dfrac{\$0.50\times (1+12\%)^4 }{(1+8\% )^{4}} + \dfrac{\$0.50\times (1+12\%)^5 }{(1+8\% )^{5}} + \dfrac{\$53.8773}{(1+8\% )^{5}} \bigg)

\implies \bigg (\dfrac{\$0.5600}{1.0800}+\dfrac{\$0.62720}{1.16640}+\dfrac{\$0.70246}{1.2597}+\dfrac{\$0.78676}{1.3605}+\dfrac{\$0.88117}{1.4693}+ \dfrac{\$53.8773}{1.4693} \bigg)

=$39.460

As a result, the price is $39.460, and the other strategy would raise the value of the shareholders. Not this one, since paying a 100% dividend would result in a price of $54.20, which is higher than the current price.

Notice that the third question depicts the situation after 5 years, but the final decision will be the same since we are discounting in current terms. If compounding is used, the future value over 5 years is just the same as the first choice, which is the better option.

The presumption in the second portion is that after 5 years, the steady growth rate would be the same as measured in the first part (1).

8 0
3 years ago
When launching a new venture, finding a way to begin doing business must ______________ generate cash flow, build credibility, a
dsp73

Answer: evaluate

Explanation:

7 0
3 years ago
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