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3 years ago

Please help asap im begging

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

6 0

Please help I will help you you can help me and I help you 1. Why must Lincoln Douglas treat each resolution independently to determine
burdens/values?
First I hope you those mask you can do math I will help you toAnswer is 40 524-678 9 10 into the answer of your math question you have to ask your math teacher Mr. Philip Sims

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The average cost of an IRS Form 1040 tax filing at Thetis Tax Service is $138.00. Assuming a normal distribution, if 77 percent

jek_recluse [69]

Answer:

22.97

Step-by-step explanation:

Given that the average cost of an IRS Form 1040 tax filing at Thetis Tax Service is $138.00.

Let x be the average cost an IRS Form 1040 tax filing at Thetis Tax Service

$P(X$ is given

From std normal distribution table we find 77th percentile z value.

z=0.74

Corresponding X value = 155

i.e. $0.74=\frac{155-138}{s}$ where s is the std deviation

Simplify to get

Std deviation = $\frac{17}{0.74} \\=22.97$

8 0

2 years ago

Can anyone help me !

murzikaleks [220]

Answer:

I think it's AB=BC.

Step-by-step explanation:

*I'm not in college, nor anywhere near college-level math, just a heads-up.*

Anyway, here's what I think. I turned my head around a bit to different angles, and I noticed the angle AB is the exact same length as BC, and both make the triangle a right angle. Try it if ya want, and see what happens. Sorry if this's wrong. I do hope it helps!

4 0

3 years ago

Read 2 more answers

8m + 7 = 5m +16 what is this answer

Sophie [7]

M equals 3.
That's your answer

5 0

3 years ago

Read 2 more answers

Find m∠U. Write your answer as an integer or as a decimal rounded to the nearest tenth.

galina1969 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

$ut = \sqrt{ {6}^{2} + {5}^{2} } \\ \sqrt{36 + 25} \\ \sqrt{61 } \\ using \: cosine \: rule \\ cos \: u = \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times \sqrt{61} } \\ \\ = \frac{25 + 61 - 36}{78} \\ \\ = \frac{50}{78 } \\ \cos \: u = 0.64 \\ m \:u = 50.2$

6 0

2 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0

3 years ago