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Bas_tet [7]
2 years ago
15

For any number n>1, is |(0.8 + 0.8i)| a. Greater than 1? b. Less than 1? c. Equal to 1?​

Mathematics
1 answer:
Genrish500 [490]2 years ago
5 0

Answer: the answers is a

Step-by-step explanation:

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What is the degree of the power function represented in the table?
allochka39001 [22]

Answer:

3

Step-by-step explanation:

-2+1= -1

4-3=1

-3/1= -3

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3 years ago
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What is the ratio 28 : 4 in it's simplest form?
Lisa [10]

Answer:

7:1

Step-by-step explanation:

28:4=

7(4):1(4)=

7:1

Hope this helps!

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3 years ago
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What is “One third of the opposite of a number is less than 12?”
nirvana33 [79]

Answer:

\frac{1}{3}(-x)<12

4 0
3 years ago
Help asap check picture
Rudik [331]

The answer will be option D {(R,1),(R,2)(R,3)(R,4(R,5)(R,6),(B,1)(B,2)(B,3)(B,4)(B,5)(B,6).

<h3>What is probability?</h3>

The probability is defined as the chances of happening of any random event. or the possibility of happening of any event is called as the probability.

It is given in the question that there are two colours in the spinner and the dice have 6 faces from {1 to 6} numbers on it.

The sample outcomes with the spinner and the dice will be as follows:-

S= {(R,1),(R,2)(R,3)(R,4(R,5)(R,6),(B,1)(B,2)(B,3)(B,4)(B,5)(B,6).

Hence  answer will be {(R,1),(R,2)(R,3)(R,4(R,5)(R,6),(B,1)(B,2)(B,3)(B,4)(B,5)(B,6).

To know more about probability follow

brainly.com/question/24756209

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5 0
2 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
2 years ago
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