Let a = 10 and b = 30 be the two given sides
Call the third side c. We cannot find the value of c but we can find the range of what it could be.
It turns out that
b-a < c < b+a
where 'b' is larger than 'a'
So this means
b-a < c < b+a
30-10 < c < 30+10
20 < c < 40
So the third missing side is between 20 and 40. It cannot equal 20. It cannot equal 40.
With this in mind, the answers are choice B) 21 and choice C) 35 since these values are between 20 and 40 (excluding the endpoints)
Note: I'm using the triangle inequality theorem
192.
Multiply 8 and 3 to figure out how many seats are being saved and subtract that for the final result.
Hope this helps!
The center points , so the ones with a full line divide by 2
Taisha is making gift bags for birthday. She intends to fill each bag with ½ pound of chocolate. Her chocolate bag weighs 4 ¾ pounds. Taisha can make 9.5 gift bags for the birthday.
This is calculated as,
There are 4 ¾ pounds of chocolate.
Each bag will have ½ pound of chocolate.
½ pound × Gift bags = 4 ¾ pounds.
4 ¾ pounds ÷ ½ pound = Gift bags.
4 ¾ pounds is 4.75 pounds and ½ pound is 0.5 pounds.
4.75 pounds ÷ 0.5 pound = 9.5 bags.
Hence , Taisha could make 9.5 gift bags for the birthday.
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