X^2-8x+16/5x^2-19x-4
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Remember that for a quadratic function of the form 
we can find its vertex with formula: 
where 
is the x-coordinate of the vertex; then we will find the y-coordinate by replacing in our original function.
From the question know that
and 
, so lets replace those values in our vertex formula to find the x-coordinate of our vertex:
Now lets replace that value into our original function to find the y-coordinate of our vertex:
Finally, we have our vertex (6,-9)
Now to graph our function we are going to take advantage of its line of symmetry; if the vertex is (6,-9) the line of symmetry of the parabola is x=6, so if we chose the point (6,0), our second point will have coordinates (3,0) as you can see in the picture.
From the question know that
Now lets replace that value into our original function to find the y-coordinate of our vertex:
Finally, we have our vertex (6,-9)
Now to graph our function we are going to take advantage of its line of symmetry; if the vertex is (6,-9) the line of symmetry of the parabola is x=6, so if we chose the point (6,0), our second point will have coordinates (3,0) as you can see in the picture.