Answer:
6.21 seconds
Step-by-step explanation:
The position function of a free-falling object is,
![s(t) = -16t^2+v_0t+s_0](https://tex.z-dn.net/?f=s%28t%29%20%3D%20-16t%5E2%2Bv_0t%2Bs_0)
Where,
= initial height of the object,
= initial velocity of the object,
Here,
![s_0=400\text{ feet}](https://tex.z-dn.net/?f=s_0%3D400%5Ctext%7B%20feet%7D)
![v_0=35\text{ feet per sec}](https://tex.z-dn.net/?f=v_0%3D35%5Ctext%7B%20feet%20per%20sec%7D)
Hence, the height of the ball after t seconds,
![s(t)=-16t^2+35t+400](https://tex.z-dn.net/?f=s%28t%29%3D-16t%5E2%2B35t%2B400)
When s(t) = 0,
![\implies -16t^2+35t+400=0](https://tex.z-dn.net/?f=%5Cimplies%20-16t%5E2%2B35t%2B400%3D0)
![t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-35%5Cpm%20%5Csqrt%7B35%5E2-4%5Ctimes%20-16%5Ctimes%20400%7D%7D%7B2%5Ctimes%20-16%7D)
![t=\frac{-35\pm \sqrt{1225+25600}}{-32}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-35%5Cpm%20%5Csqrt%7B1225%2B25600%7D%7D%7B-32%7D)
![\implies t\approx -4.02\text{ or }t\approx 6.21](https://tex.z-dn.net/?f=%5Cimplies%20t%5Capprox%20-4.02%5Ctext%7B%20or%20%7Dt%5Capprox%206.21)
∵ Time cannot be negative,
Hence, after 6.21 seconds the ball will reach the ground.
Answer:
It takes 4 minutes per block and she can walk 12.5 blocks in 45 minutes.
Step-by-step explanation:
20 / 5 = 4 minutes per block
20 + 20 + 5 = 45
5 + 5 + 2.5 = 12.5
Hope this helps, I did the test last year.
Y=-1/20(x+3)^2
Your could always tell by which way the curve is pointing and if pointing down it’s a negative it’s pointing up it’s a positive
Hope that helped
Answer:
Line R
Step-by-step explanation: