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3 years ago

I need to answer A and B

Mathematics

1 answer:

ycow [4]3 years ago

8 0

675840 feet that's the answer I'm sure of it

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The seats at a local baseball stadium are arranged so that each row has five more seats than the row below it. If there are 4 se

nordsb [41]

Givens:

a = 4; n = 23; d = 5

Formula

L = a + (n - 1)*d

Substitute and solve

L = 4 + (23 - 1)*5

L = 4 + 22*5

L = 4 + 110

L = 114 Answer

4 0

3 years ago

HELP PLZZZZZZZ STANDARD FORM

liraira [26]

Answer:

- $12n^{2}$ + 12

Step-by-step explanation:

h(n) = -4n + 4 (h o g) (n)

g(n) = $3n^{2}$ - 2

-4( $3n^{2}$ - 2) + 4

- $12n^{2}$ + 8 + 4

- $12n^{2}$ + 12

7 0

3 years ago

What is the equation of the line through (5, 1) with a slope of -3?

Vlad1618 [11]

Answer:

B. y-1=3(x-5)

Step-by-step explanation:

y=_+_(x-_)

y=1+(-3)(x-5)

y-1=3(x-5)

6 0

3 years ago

How is the series 5+11+17…+251 represented in summation notation?

NISA [10]

Answer:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

Step-by-step explanation:

Given:

Series 5+11+17+...+251

To find:

Summation notation of the given series

Summation Notation:

$\displaystyle \large{\sum_{k=1}^n a_k}$

Where n is the number of terms and $\displaystyle \large{a_k}$ is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

Arithmetic Series

A series that has common difference.

Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

11-5 = 6
17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

$\displaystyle \large{a_n=a_1+(n-1)d}$

Where $\displaystyle \large{a_n}$ is the nth term, $\displaystyle \large{a_1}$ is the first term and $\displaystyle \large{d}$ is the common difference:

So for our general term:

$\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}$

And for number of terms, substitute $\displaystyle \large{a_n}$ = 251 and solve for n:

$\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}$

Now we can convert the series to summation notation as given the formula above, substitute as we get:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

5 0

2 years ago

Help with this please free brainlist i promise only if you get it right though

goldenfox [79]

Answer:eirther C or D not sure

Step-by-step explanation:

5 0

3 years ago