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IceJOKER [234]
3 years ago
13

If you had a triangle with side lengths of 4 and a scale factor of 3, what would be the new side lengths of the triangle?

Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

1.3

Step-by-step explanation:

new side lengths = original length / scale factor

4/3 = 1.3

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Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
Find an expression which represents the sum of (-8x+7y)(−8x+7y) and (2x-2y)(2x−2y) in simplest terms.
Yakvenalex [24]

Answer:

(-8x+7y)(−8x+7y)+(2x-2y)(2x−2y)= simplified - 68x^2+53y^2−120xy

I hope this helps ! <3

Step-by-step explanation:

3 0
3 years ago
a satelite moves at the speed of 27,000 kilometers per hour what 4 number could be the actually speed of the satelite
Anvisha [2.4K]
If the satellite moves at a speed of 27,000 km p/h, your answer depends on the question.

This could be written in an algebraic expression, such as:

27,000x = S                 [for S stands for the ultimate speed of the satellite]

Of course, if this is a 3rd grade level question, I highly doubt they have even gotten started to including the alphabet into math. 

So, I would suggest plugging 4 into X.
To explain this to her, just say that the speed needs to be multiplied by the amount of hours it has traveled. (I got 4 because there is a '4' in the question instead of 'for').

Meaning,  
27,000 x 4 = 108,000 km per 4 hours

If her teacher decides to ask why that number, have her explain the question did not make sense so she plugged in a 4 to find an answer to a certain amount of hours. 

Hope that helps a bit with the confusion!
7 0
3 years ago
Instructor Vallejo is trying to figure out the percentage of students that still listen to The Doors. Instructor Vallejo
tatiyna

Answer:

N=115

Step-by-step explanation:

n=.25(2.5715/.12)^2 =114.8 so round up to 115. Hope that help you

3 0
3 years ago
Solve the equation x^2-18x+21=-3x to the nearest tenth
pav-90 [236]

Answer:

x=1.6 and x=13.4

Step-by-step explanation:

First we must bring -3x over to the left side by addin git the both sides

4 0
2 years ago
Read 2 more answers
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