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3 years ago

13

If you had a triangle with side lengths of 4 and a scale factor of 3, what would be the new side lengths of the triangle?

1 answer:

Stels [109]3 years ago

8 0

Answer:

1.3

Step-by-step explanation:

new side lengths = original length / scale factor

4/3 = 1.3

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<span>-1 + n=8(n+6)
Use distributive property
-1 + n= 8n + 48
Subtract n from both sides
-1= 7n + 48
Subtract 48 from both sides
-49= 7n
Divide 7 on both sides so that the only thing remaining on the right sides is the varible n.
Final Answer: -7 = n</span>

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Answer:

A=25 (Rounded)

Step-by-step explanation:

The first step is to find the length of BA which is the base, then you have the find the length of CD, the hight.

To find the distance, you need to use the distance formula which is

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$ (It does not matter if A is x1 or is B is x1, it just has to remain consistent)

I am going to first find BA

$d=\sqrt{\left({-7}-{-1}\right)^{2}+\left({-1}-{5}\right)^{2}}$

Next, subtract accordingly

$d=\sqrt{\left({-7}+{1}\right)^{2}+\left({-1}-{5}\right)^{2}}$

$d=\sqrt{\left({-6}\right)^{2}+\left({-6}\right)^{2}}$

Once you do that, you want to square -6 and -6 which will give you

$d=\sqrt{\left({36}\right)+\left({36}\right)}$

Now add 36 with 36 which will leave you with

$d=\sqrt{{72}}$

Do that same thing for CD. If you did it right, you should be left with

$d=\sqrt{{18}}$

to find the area of a triangle, you must use the formula

$A=\frac{B*H}{2}$

The Base is $\sqrt{{72}}$ (BA) and the Hight is $\sqrt{{18}}$ (CD). substitute to get

$A=\frac{\sqrt{{72}}*\sqrt{{18}}}{2}$

Multiply the Base by the Hight to get

$A=\frac{\sqrt{{1,296}}}{2}$

Divide 1,296 by 2 to get

$A=\sqrt{{648}}$

Which is equal to

$A=25.455844122715710878430397035775$

Rounding it to the nearest whole number you get

A=25

Hope this helps. Feel free to ask any follow-up questions.

Have a good day! :)

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