Numbers are arranged by their place values. Place values give a quantity of value to a certain digit in a number. Given a number, the rightmost number is the ones place, followed by the tens place, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, hundred millions, as so on and so forth. The place value of a certain digit is 10 times bigger than its adjacent digit to the right.
So for this problem, all you have to do is multiply the number of units of each place value, then multiple them all by 10.
(2(10) + 1(1))×10
21 × 10 = 210
Therefore, the number is equivalent and written as 210.
Answer:
Step-by-step explanation:
So we have the equation:
And we want to solve for g.
First, isolate g. To do so, subtract vt from both sides:
Multiply both sides by 2:
Now, divide both sides by t^2:
Expand:
Simplify the second term:
And we're done!
Y=11 x=13
It’s a rectangle so each angle equals 90
1
Angle 1 + angle 2 =90
5y+2y+13=90
7y=77
y=11
Th diagnose of a rectangle bisect so 8x-16=5x+23
3x=39
X=13
Step-by-step explanation:
Left hand side:
4 [sin⁶ θ + cos⁶ θ]
Rearrange:
4 [(sin² θ)³ + (cos² θ)³]
Factor the sum of cubes:
4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]
Pythagorean identity:
4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]
Complete the square:
4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]
4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]
Pythagorean identity:
4 [1 − 3 sin² θ cos² θ]
Rearrange:
4 − 12 sin² θ cos² θ
4 − 3 (2 sin θ cos θ)²
Double angle formula:
4 − 3 (sin (2θ))²
4 − 3 sin² (2θ)
Finally, apply Pythagorean identity and simplify:
4 − 3 (1 − cos² (2θ))
4 − 3 + 3 cos² (2θ)
1 + 3 cos² (2θ)
Answer:
Plain is $7 and Holiday is $15
Step-by-step explanation:
Castel: 2p + 5h = 89
Kali: 9p + 10h = 213
Double Castel's: 4p + 10h = 178
Subtract fro Kali's 9p + 10h = 213
- 4p + 10h = 178
5p = 35
p = 7 Plain is $7
Substitute 7 into one of the equations and solve for h:
2(7) + 5h = 89
14 + 5h = 89
5h = 75
h = 15 Holiday is $15
