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Levart [38]
3 years ago
12

A rectangular park has sidewalks on two adjacent sides. If it takes John 60 steps to

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

Length = 80 m and breadth = 60 m If one moves along the two adjacent sides, one covers 80+60 = 140 m. Diagonal of the rectangle = √ ( length^2 + breadth^2) ...

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Houw would i factor this problem out completely?
kvasek [131]
You can factor out a 3t first, resulting in:
3t(2t^2+3t-5)

Now, let's factor the equation in the middle using the quadratic equation. Plug in the values to the quadratic equation:
\frac{-3\pm \sqrt{3^2-4(2)(-5)}}{2(2)} = -\frac{3\pm \sqrt{49}}{4} = -\frac{3\pm 7}{4}

Simplify, you get your x's:
x = 1, -\frac{5}{2}

To write the equation in simplified form, you just write it this way:
3t(x-1)(2x+5)

That's your answer ^
3 0
3 years ago
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3 0
3 years ago
A(t) = (t – k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.
mr Goodwill [35]

the absolute value of the product of the zeros of a is -108 .

<u>Step-by-step explanation:</u>

Here we have , a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.  Given that a(2) = 0 . We need to find the  absolute value of the product of the zeros of a . Let's find out:

Equation every factor of a(t) to zero we get:

⇒ a(t) = (t - k)(t - 3)(t - 6)(t + 3) = 0

⇒ (t - k) =0\\(t - 3)=0\\(t - 6)=0\\(t + 3) = 0

⇒ t  =k\\t =3\\t = 6\\t =- 3

But , t=2 So , k=2  . Now , the absolute value of the product of the zeros of a is :

⇒ k(3)(6)(-3)

⇒ 2(3)(6)(-3)

⇒ -108

Therefore, the absolute value of the product of the zeros of a is -108 .

4 0
3 years ago
What is the product (x-3)(2x^2-5x + 1)
Reika [66]
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</span>
4 0
3 years ago
A rock is thrown upward with a velocity of 18 meters per second from the top of a 37 meter high cliff, and it misses the cliff o
zhenek [66]

Answer:the rock would be at a point 12 m from water

Step-by-step explanation:

8 0
3 years ago
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