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3 years ago

Consider -103/-3. Which statements are correct?

Mathematics

2 answers:

kirill [66]3 years ago

7 0

Answer:

D is the correct answer

Step-by-step explanation:

negative ÷ negative = positve

My name is Ann [436]3 years ago

7 0

Answer:

Explanation

A) and B) are false because -103/-3 is equal to 34.3333....

C) The quotient of two negatives is always negative. ⇒ False because D) is true

D) The quotient of two negatives is always positive. ⇒ True

E) The integer with the greatest absolute value always determines the

quotient's sign ⇒ False because D) is true

I hope this helps!

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If ABC=DEF and MNO=PQR, then ABC=PQR by the transitive property.

zavuch27 [327]

Answer:

B. False

Step-by-step explanation:

There is not enough information to make that conclusion. The two statements are completely unrelated, so the transitive property cannot be used. None of the given statements say that ABC is congruent to MNO or PQR. That means that nothing can be assumed about DEF. To use the transitive property you would need proof that ABC=MNO or ABC=PQR. But neither of those statements are there so the answer is false.

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3 years ago

Which shows a perfect square trinomial?

Tju [1.3M]

The third one. Because it factors to (4x+3y)^2

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3 years ago

Read 2 more answers

Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among

Olegator [25]

Answer:

a) X[bar]₁= 1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= $\frac{1}{n_1-1}$ [∑X₁² - (( ∑X₁)²/n₁)]= $\frac{1}{14} + [52829538 - (\frac{27588^{2} }{15})$ = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

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