Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer:
(n/3)-10=6
Step-by-step explanation:
Let n be the number
Quotient of n and 3 is n/3
10 less that this is (n/3)-10=6
Answer: quotient is 2x^2 + 10x - 5
Solution:
The first polynomial is miswritten.
The right one is: 2x^3 + 4x^2 - 35x + 15.
So, the division is [2x^3 + 4x^2 - 35x + 15] / (x - 3)
The synthetic division uses the coeffcients and obviate the letters, but you have to be sure to respect the place of the coefficient.
So, in this case it is:
3 | 2 4 -35 15
---------------------------------
2 10 - 5 0
So, the quotient is 2x^2 + 10x - 5, and the remainder is 0.
I like to show it in this other way:
| 2 4 -35 15
|
|
3 | +6 +30 -15
--------------------------------
2 10 - 5 0
Of course they are the same coefficients and the answer continue being quotien 2x^2 + 10x - 5, remainder 0.
Answer:
its open
Step-by-step explanation:
i just did it
Answer: Let me try to figure this out but this is not 7-8 grade math level
Step-by-step explanation:
