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emmasim [6.3K]
3 years ago
8

My last math question! Plz help if you can and it asks for the elimination method. thank you!

Mathematics
1 answer:
Galina-37 [17]3 years ago
6 0
I've found a Programm that calculates it for you...
x=0.6666667
I don't know if that's correct or helpful but here you go :)
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The table shows the pricing for four different brands of cat food.
Nadya [2.5K]

Answer:

c

Step-by-step explanation:

a: 0.88 ÷ 4 = $0.22 per ounce

b: 1.05 ÷ 5 = $0.21 per ounce

c: 1.6 ÷ 8 = $0.1875 per ounce

d: 2.28 ÷ 12 = $0.19 per ounce

8 0
3 years ago
Read 2 more answers
The table shows the cost of posting parcels.
alexandr402 [8]

Jake wants to post a 600 gram parcel and an 800 gram parcel.

He posts them Second Class.

He pays with a £10 note.

How much change should he get?

3 0
2 years ago
Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360° ​
vodka [1.7K]

2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x  -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or}  ~~u =\dfrac{-4}{4} =-1\\\\

\implies \tan x = \dfrac 12 ~~ \text{or} ~~  \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\

x=\tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,}   ~~x=\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\

\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]

4 0
2 years ago
Each of the students im Romi's class raised at least $25 during the jump-a-thon. What is the least amount of money the class rai
EastWind [94]
If each of the 28 students made at least $25, you would multiply 28 and 25 together to obtain the least amount of money the class raised. That gets, 28x25 = 700. The class made at least $700.
8 0
3 years ago
Rewrite the expression as an equivalent expression that does not contain powers of trigonometric functions greater than 1.
stich3 [128]
We are asked to express cos^ 3 x in terms of  powers of trigonometric functions not greater than 1

cos ^ 3 x is equal to cos x * cos^2 x. 
<span>cos^2 x = 1 - sin^2 x.
</span>sin^2 x  = (1 - cos 2x) /2 

the answer is cos ^ 3 x = cos x * (1 - <span> (1 - cos 2x) /2 )</span>




5 0
3 years ago
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