Answer:
Since the null hypothesis is true, finding the significance is a type I error.
The probability of the year I error = level of significance = 0.05.
so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5
Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.
The answer for this question when grouping:
(x+2)(3x^2+1)
Solve x by simplifying both sides of the equation & then isolating the variable x=-4 & the negative comes in from the -12
Answer:
5.7 units
Step-by-step explanation:
By geometric mean property:
